What are the minimum number of 2 to 1 multiplexers required?

Detailed Solution. We need to implement 4 to 1 Mux using 2 to 1 Mux. We need 4/2 = 2 in first level and 2/2 = 1 in second level. Hence, we need three 2 to 1Multiplexers to implement 4 to 1 Mux.

Which IC is used for the implementation of 16 to 1 mux?

These multiplexers are available in IC forms with different input and select line configurations. Some of the available multiplexer ICs include 74157 (Quad 2-to-1 MUX), 78158 (Quad 2-to-1 MUX with inverse output), 74153 (4-to-1 MUX), 74152 (8-to-1 MUX) and 74150 (16-to-1 MUX).

How many 5 input AND gates are required to design a 16 1 multiplexer?

16×1 Multiplexer We know that 8×1 Multiplexer has 8 data inputs, 3 selection lines and one output. Whereas, 16×1 Multiplexer has 16 data inputs, 4 selection lines and one output. So, we require two 8×1 Multiplexers in first stage in order to get the 16 data inputs.

How many and Gates does a 16×1 MUX require?

4 transmission gates
5.2. A 16X1 MUX offers a load of 4 transmission gates to its inputs. A Tri-State MUX is one which along with driving the data (either 0 or 1) to the output can also result high impedance state.

How many data select lines are required for selecting 16 inputs in 16 1 mux?

How many 2 1 mux are required to construct and gate and EX OR gate?

c) Implementation of OR gate using 2 : 1 Mux using “n-1” selection lines. Implementation of NAND, NOR, XOR and XNOR gates requires two 2:1 Mux. First multiplexer will act as NOT gate which will provide complemented input to the second multiplexer. Three(3) ​2 : 1 MUX are required to implement 4 : 1 MUX.

How many MUX do I need?

answer is B) 32 mux are required .

What is the IC number of 1-to-16 demux?

74154
These are available in different IC packages and some of the most commonly used demultiplexer ICs includes 74139 (dual 1:4 DEMUX), 74138 (1:8 DEMUX), 74237 (1:8 DEMUX with Address Latches), 74154 (1:16 DEMUX), 74159 (1:16 DEMUX open collector type), etc.

How do you make a 5 to 1 mux?

1) Take a 4-to-1 mux, connect A1-A4 and S0-S1 to it. Take the output of the 4-to-1 mux and connect it to one input of a 2-to-1 mux. Connect A5 and S2 to the remaining pins. Now you have a 5-to-1 mux.