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Why N CH3 3 is pyramidal but N SiH3 3 is trigonal planar?

Why N CH3 3 is pyramidal but N SiH3 3 is trigonal planar?

In case of N(CH3)3, PΠ-PΠ bonding occur between N and C atom. thus N has sp3 hybridisation with pyramidal shape. But in case of N(SiH3)3, pπ-dπ bonding( back bonding) occur. thus N has sp2 hybridisation with planar shape.

Why is SiH3 3p pyramidal?

(CH3)3N and (SiH3)3P have pyramidal geometry due to absence of back bonding. Nitrogen and Phosphorus are sp3 hybridized out of which 3 hybrid orbitals are used for bond making and 1 lone pair is present in fourth orbital. Hence option (b) is correct.

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Which structure is planar CH3 3n?

(CH3​)3​ N is pyramidal but (SiH3​)3​ N is trigonal planar.

Why trimethylamine is pyramidal and Trisilylamine is planar?

The structure of trisilylamine is planar due to the presence of bonding. In the molecule trisilylamine has vacant d-orbitals which are present in their central atom sulphur. Therefore, the structure of trimethyl amine is pyramidal shape whereas trisilylamine has planar shape.”

What is the geometry of N SiH3 3?

(a) (CH3)3N is pyramidal in shape while (SiH3)3N is planar.

Why SiH3 3N is a weaker base than ch3 3N?

The atom in Trimethylamine (ch3)3N is pyramidal due to sp3 hybridisation and due to lone pair – bond pair repulsion. Thus the involvement of lone pair in d pi – p pi bond makes (Sih3)3N a weaker base than (ch3)3 N.

Why there is no back bonding in P SiH3 3?

The back bonding in P(SiH3)3 isn’t significant like in N(SiH3)3 bcz P has its 3p orbital (large and not so efficient) whereas N has its 2p orbital, more efficient bonding.

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What is the hybridisation of N in N CH3 3 and n SiH3 )?

sp^3 –
N(CH3)3 and N(SiH3)3 both have sp^3 – hybridized N – atom and Pyramidal structure.

Why SiH3 3N is a weaker base than CH3 3N?

Why is trisilylamine planar?

Trisilylamine has a planar geometry because it has backbonding. Silicon has vacant d-orbitals. The lone pair on the Nitrogen atom provides the vacant d-orbital of silicon with electrons. And $s{{p}^{2}}$ hybridization shows trigonal planar geometry, therefore the shape of trisilylamine is trigonal planar.

Which is more basic N CH3 3 or N SiH3?

Lone pair of electrons on N in N(SiH3)3 are used up in p-pie d-pie back bonding while in N(CH3)3 such back bonding is not possible due to the absence of vacant d-orbital in carbon. Therefore, N(CH3)3 is more basic than N(SiH3)3.