What is the resultant temperature when one gram of ice at zero degree Celsius and 1 gram of steam at hundred degree Celsius are mixed?

if 1 g of steam is mixed with 1 g of ice, then the resultant temperature of the mixture is. Heat requiired by 1 g ice at 0∘C to ment into 1 g water at 0∘C. Obvioulsy, the whole steam will not be condensed and ice will attain temperature of 100∘C. Thus, the temperature of mixture is 100∘C.

What is the resultant temperature of 1g of ice?

2 Answers. Melting of 1g ice to 1g water at 0°C requires 80cal heat gained. Heat required to raise this 1g water at 0°C to 100°C is 100cal. So this total 180cal heat can easily be available from steam.

When 1g of ice is mixed with 1g of steam?

At thermal equilibrium, the temperature of the mixture is. As Q1<Q2, whole of the steam will not condense, so the temperature of the mixture is 100∘C.

What is the minimum amount of ice at 0 C is required to condense 100 g steam at 100 C?

1 g of ice at 0^oC is converted to steam at 100^oC .

How much heat does 50g ice absorb from steam?

The 50 g ice at 0 deg. absorb (50*80 cal =) 4000 cal heat and become 50 g of water at 0 deg. The heat released by the steam is greater than the heat absorbed by the ice. And the released heat must be equal to the absorbed heat. So, 1st ice absorbs 4000 cal and converts into the water.

How much heat does it take to melt 540g of ice?

Heat required to melt 540g of ice at 0°C to 540g of water at 0°C = 540 × 80 = 43,200 calorie. So the heat released by steam would melt the ice to water. But the condensing 80g of steam is at 100°C, whereas 540g of melted ice is at 0°C.

How much heat is released when steam is heated?

There are two things – 10 g of steam at 100 deg and 50 g of ice at 0 deg. The 10 g steam at 100 deg. release (10*540 cal =) 5400 cal heat and become 10 g of water at 100 deg. The 50 g ice at 0 deg. absorb (50*80 cal =) 4000 cal heat and become 50 g of water at 0 deg. The heat released by the steam is greater than the heat absorbed by the ice.

What is the resultant temperature of mixture at thermal equilibrium?

At thermal equilibrium, the resultant temperature of mixture is 1 g of steam is sent into 1 g of ice. At thermal equilibrium, the resultant temperature of mixture is Please log in or register to add a comment. Melting of 1g ice to 1g water at 0°C requires 80cal heat gained. Heat required to raise this 1g water at 0°C to 100°C is 100cal.