How many numbers less than 1000 and divisible by 5 can be formed no digit being repeated?

> Condition 1: For a number to be divisible by 5, its unit digit must be “0” or “5”. Now, for all natural numbers from 1 to 999 (because the question says less than 1000), 199 natural numbers satisfy this. * Thus, 199 natural numbers.

What is the number of numbers less than 1000 and divisible by 5 which can be formed with digits 0 to 9 such that no digit gets repeated?

If the last digit is 0, then the number of ways for the first digit = 9 and for the 2nd digit it will be 8 ways. If the last digit is 5, then the number of ways for the 1st digit = 8 and for the 2nd digit is 8 as this time 0 can be placed in the 2nd digit. Thus, Total number of numbers = 1 + 17 + 136 = 154 ways.

How many numbers can be formed from some or all of the digits 2 3 4 5 if number do not have repeated digits?

Total Number of Numbers which can be formed by numbers 1,2,3,4,5 (without repeating digitsi) = 5*4*3*2*! = 5! = 120.

How many 4 digit numbers can be formed by using 1 to 7 which are greater than 3400?

Answer: 3400 ¹p1 * ⁴p1 * ⁵p2 = 80.

How many numbers between 400 and 1000 can be formed with the digits?

So, the required number of numbers is 60.

How many natural numbers less than 1000 can be formed with the digits 1.2 3.4 and 5 if Repetation is allowed?

Answer: Total digit 216. To find : How many natural numbers less than 1000 can be formed from the digits 0, 1, 2, 3, 4, 5 when repetition of digits are allowed? Choose the second digit any of 6 ways.

How many odd numbers are there between 1000 and 10000 which have none of their digits repeated?

4536 numbers
Show that there are 4536 numbers between 1000 and 10000, which have none of their digits repeated.

How many numbers greater than 23000 can be formed with 12345?

The answer is 120 numbers (5!).

How many numbers each consisting of four different digits can be formed with the digits 0 1 2 and 3?

Hence 18 numbers can be formed with the digits 0,1,2,3 with all distinct digits.