How many 4 digit numbers can be formed using the digits 9 8 7 6 5 if no digits are repeated?

Answer: → 4 digits numbers can be arranged in = 4! = 4 * 3 * 2 = 24 ways . therefore, → Total number of ways = 15 * 24 = 360 (Ans.)

How many numbers greater than 600 can be formed with the digits 5 6 7 8 if no digit is used more than once in a number?

The four digit numbers will all be bigger than 600. There are 4*3*2*1 such numbers, which is 24 numbers. So the total possible is 18+24, which is 42. (HHGTTG strikes agian!)

How many four digit numbers can be formed with the digits 3 5 7 8 9 which are greater than 7000 if repetition of digits is not allowed?

Here, the required numbers are greater than 7000. Therefore, the thousand’s place can be filled with any of the 3 digits: 7, 8, 9. Thus, the total number of possible outcomes is 3C1 × 4C1 × 3C1 × 2C1 = 3 × 4 × 3 × 2 = 72.

How many 3 digit numbers are there more than 600?

so total numbers which is greater than 600 are = 2*3*6 = 36.

How many 4 digit number can be formed by using the digits 0 9?

We can only use 5 numbers for the fourth digit. The number of 4 digit even numbers than can be formed using 0 to 9 is 504 * 5 = 2520.

How many numbers of 3 digit less than 500 can be formed from the integer 123456?

Answer: The numbers formed can be 60.

How many 9 digits number of different digits can be formed?

Therefore, the total number of possibilities is given by 9×9! =3265920. Hence, 9 digit numbers of different digits can be formed in 3265920 ways.

How many 4 digit numbers can be formed with the digits?

There is 4 possible ways to fill hundredth place as digits cannot be repeated. There is 3 possible ways to fill the first place of four digit number. ∴ 60 four-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9.

How many numbers between 3000 and 4000 can be formed?

60 numbers
Thus, there are 60 numbers lying between 3000 and 4000 that can be formed using the digits 3, 4, 5, 6, 7, and 8, where no digit is repeated.

How many 3 digits number can be formed using digits 1 5 7 and 9?

So, the number of 2 digit numbers is 12. For 3 digit numbers, as we have 4 intakes, 3 intakes, and 2 intakes at 1st place, 2nd place, and 3rd place respectively. So, the number of 3 digit numbers is 24.

How many three-digit numbers can be formed without repetition?

Question 865062: How many three-digit numbers can be formed using the numerals {2, 3, 4, 5, 6, 7} without repetition? You can put this solution on YOUR website! There are 6 numbers in that set given. So there are Which means that there are 6*5*4 = 30*4 = 120 different 3 digit numbers to form (without repetition).

How many numbers can be formed with 2 in the thousands?

The number of numbers that can be formed with 2 in the thousands place is 3!, i.e., 6 numbers. Hence, when 2 in the thousands place its contribution to the sum is 3! x 2000.

What is the sum of all numbers formed by using 4 digits?

Sol: Sum of the numbers formed by taking all the given n digits is (sum of all the n digits) x (n-1) ! x (111…..n times). Here n = 4. and Sum of 4 digits = 16 The sum of all the numbers which can be formed by using the digits 1, 3, 5, 7 is = (16) x (4 – 1)! x (1111)

How many ways can 5 be arranged in 5 digits?

3, 1, 7, 0, 9, 5, i.e. 6 digits. 6! – 5! = 720-120 = 600. (i) 5! = 120 having 0 at the end. (ii) Divisible by 5. They will have zero in the last place and hence the remaining 5 can be arranged in 5! = 120 ways. They may have 5 in the last place and as above we will have 5! = 120 ways.