What happens to the voltage when the switch is closed?

If there is no load connected after the closed switch, the voltage across the switch is still zero. If there is a load connected after the open switch, the voltage is dependent on the resistance of the load and probably approaches 12 volts. The voltage across the closed switch is always zero.

Does current drop across a inductor?

Under steady state AC voltage and current is there a voltage drop across an inductor? Yes, if you are talking about steady state sinusoidal signals. If you are talking about DC steady state, then the voltage is zero across an ideal inductor.

What is the current through the inductor when the switch has been closed for a long time?

By the Loop Law, V(battery voltage) = IR + LdI/dt. Immediately after the switch is closed , the current is zero (because the current thru the inductor cannot change instantly), so IR is zero, so V = L dI/dt. So dI/dt = V/L = 10V/10H = 1 A/s.

What is the current through the inductor at t 0?

At $t=0$ the voltage across the Inductor will immediately jump to battery voltage. Why? – Physics Stack Exchange.

Why is the voltage 0 when the switch is closed?

Right after the switch is closed, the charge has not had time to build up on the capacitor and the charge and voltage are still zero. The initial voltage across the far right resistor is also zero. That resistor is in parallel with the capacitor, so the voltage across the capacitor and the resistor have to be the same.

Why is the voltage across a closed switch zero?

The voltage across a closed switch will be zero volt (or close to zero) depending on the internal resistance of the switch contact. A closed switch can be seen as a simple piece of wire, with basically no volt drop across the terminals.

Why does voltage drop across a inductor?

Like a capacitor, an inductor’s behavior is rooted in the variable of time. Aside from any resistance intrinsic to an inductor’s wire coil (which we will assume is zero for the sake of this section), the voltage dropped across the terminals of an inductor is purely related to how quickly its current changes over time.

What is the current through the EMF just after closing the switch?

The current will not instantly rises to a maximum value. This is due to the presence of inductance and capacitance in the circuit. This is why we say, unlike in the resistive circuit, in an LCR circuit, the current will be zero, just immediate after the switch is closed.

What is t1 the first time after t 0 when the voltage across the inductor is zero?

The first time after t = 0 when the voltage across the inductor is zero is 1.00 ms.

When t is equal to zero the potential difference across the inductor is?

Thanks! E.g. What is the potential difference across the inductor at t = 0? through the circuit is 0.

Does current flow through capacitor at t 0?

Assuming the capacitor is not initially charged, at t=0 a current will start to flow through it, but there is zero voltage across it (because it hasn’t built up any charge).

Why is the induced voltage across an inductor always zero?

This means that when the change in the current is maximum (at current passing through zero), the voltage induced across the inductor is maximum. Similarly, at maximum values of current where current is not changing, the induced voltage across the inductor will be zero.

What is the voltage drop across inductor and resistor?

The induced voltage in the inductor opposes the flow of current and hence V L leads the current I and drop across resistance V R by 90 0. Let I be the current flowing through the circuit, V L and V R are the voltage drops across inductance and resistance respectively. Voltage across the resistor, V R = I R

Why is there no drop on the resistance of a switch?

Because there is no current the drop on the resistance is zero, that means that the voltage difference at the ends of the switch is the same as the ends of the battery.

What is the voltage drop across the open switch?

If you have an electric circuit with a 12V battery in series with an open switch and a resistor, the voltage drop across the open switch is 12V. But this doesn’t quite make sense to me.