Questions

What is the de Broglie wavelength of an electron that is accelerated from rest through a potential difference of 20 Kev?

What is the de Broglie wavelength of an electron that is accelerated from rest through a potential difference of 20 Kev?

1226 nm.

What is the de Broglie wavelength of an electron accelerated from rest through?

λ = 1.23√V nm.

What is the de Broglie wavelength of an electron accelerated from rest by a potential difference of 54 V?

Example 2: Calculate the de Broglie wavelength for an electron that is accelerated inside a potential difference of 54 volts. Solution: Using the above formula, we get: λ = 0.167 nm.

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What is the de Broglie wavelength of an electron accelerated to a potential of 400 V?

0.03 nm
The de Broglie wavelength of an electron accelerated to a potential of 400 V is approximately [Karnataka CET 2016] 0.03 nm.

What is the de Broglie wavelength of an electron accelerated through 770?

λ=0.388 nm .

What is the velocity of de-Broglie wave?

v=hvmc.

What is the de-Broglie wavelength for the electron when it is in the N 4 level?

four times
Therefore, the de-Broglie wavelength associated with the electron in the n=4 level is four times the de-Broglie wavelength of the electron in the ground state. So, the correct answer is “Option B”.

What is the de-Broglie wavelength of an electron that has been accelerated?

The de – broglie wavelength of an electron that has been accelerated through a potential difference of 100 V is: 12th

Is a de Broglie wave a wave function?

However —and this is extremely rarely emphasized— a de Broglie wave is a simple harmonic wave, for it has a well-defined (de Broglie) wavelength, λ d B = 2 π ℏ p. In turn, a wave-function can represent (and almost always does) a superposition of any number of simple harmonic waves.

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What is the work done in accelerating an electron through electric field?

So if a charge of e coulombs is moved through a potential difference of V volts then the work done is eV Joules. −1.6 x 10−19C. The work done in accelerating an electron through this electric field will be equal to the kinetic energy of the electron 1 2mv2.