How do you find the molar mass of a diprotic acid?

The molar mass of the diprotic acid is the ratio of the number of grams to the number of moles in that number of grams, which is what is determined by the titration.

What is the molecular weight of an unknown diprotic acid?

The atomic weight of the unknown diprotic acid is approximately 107.5g .

What is the molar mass of ascorbic acid?

176.12 g/mol
Ascorbic acid/Molar mass

How do you find the molar mass of an unknown?

First the ideal gas law will be used to solve for the moles of unknown gas (n). Then the mass of the gas divided by the moles will give the molar mass. Step 2: Solve. Now divide g by mol to get the molar mass.

How do you calculate pKa1?

One half-equivalence point occurs at one-half the volume of the first equivalence point, at which pH = pKa1. The second occurs at the volume that is at the midpoint between the first and second equivalence points, and at that point, pH = pKa2.

How many moles of base are in 25 ml of Koh?

You used 11.6 mL of 1.00 mol/L KOH. That gives 0.0116 moles of base. Since the acid is diprotic, you had half that number (0.00580 moles) for the acid. That’s just the amount of acid in 25 mL. The amount in the original 200 mL solution is 0.0464 moles.

What is the molar mass of 25 ml of acid?

Since the acid is diprotic, you had half that number (0.00580 moles) for the acid. That’s just the amount of acid in 25 mL. The amount in the original 200 mL solution is 0.0464 moles. This means the molar mass will be 4.50 g / 0.0464 moles, or 97.0 g/mol.

How to find the number of moles of acid in titration?

Remember, number of moles of acid is not the answer. You must find molar mass which is grams per mole. Titrations are really stoichiometry problems, but the formula of the acid is unknown. return to GenChem Home Page

How do you calculate the molar mass of a base?

To calculate the molar mass, you need to know the mass of the sample, and how many moles the sample contains. Since the first is given, let’s look at the second part. You used 11.6 mL of 1.00 mol/L KOH. That gives 0.0116 moles of base.