What mass of KOH should be dissolved in one Litre of solution to prepare a solution having pH is 12 at 25 C?

How much KOH should be dissolved in one litre of solution to prepare a solution having a pH of 12 at 25^@C? In a solution having pH =12, the hydrogen ion concentration is given by the equation. Thus, 0.56g of KOH should be dissolved per litre solution to obtain a solution of pH 12.

What mass of KOH would need to be dissolved in 500.0 mL of water?

1 Expert Answer 0.0251 moles / L x 17.0 g/mole x 1L/1000 mL x 500 mL = 0.213 g OH-. The mass of KOH needed then is molar mass KOH / molar mass OH- x g OH-. 56.1 g / 17.0 g x 0.213 g OH- = 0.703 g KOH.

How do I make a KOH pellet solution?

for preparing 60\% KOH solution, you have to just weigh 600 g pellets of KOH and dissolve in 1000 ml of distilled water (or, 60 g KOH pellets dissolved in 100 ml distilled water.

How many grams of Naoh must be dissolved in one Litre of the solution to give it a pH value of 12?

2 g L−1.

How many grams of Naoh must be dissolved in one Litre of the solution to give it a ph value of 12?

What mass of Koh should be dissolved in one litre solution?

– Quora What mass of KOH should be dissolved in one litre of solution to prepare a solution having pH of 12 at 25°C? At pH = 12, the concentration of OH- is 0.01 M. Since you want to make 1 liter of this solution you will need 0.01 moles of KOH.

How do you calculate the pH of a KOH solution?

Calculate the theoretical pH value of the KOH solution. According to the theory 1, OH – concentration is 0.1 mol dm -3 Now, you can use the equation 3 to calculate pOH with known OH – concentration. pOH = -log 10 [0.1] pH of 0.1 mol dm-3 KOH solution is 13.

How many moles of Koh are needed to make 1 liter?

At pH = 12, the concentration of OH- is 0.01 M. Since you want to make 1 liter of this solution you will need 0.01 moles of KOH. Since KOH weighs 56.11 g/mole, you will need: Now, I don’t like the way you asked the question. You should not just add this amount of KOH to a liter of water and call it a day.

What is the concentration of [Oh-] of Koh?

As KOH is a strong base the [OH-] concentration will equal that of the initial substance due to complete dissociation. pOH = – log [OH-] pOH=-log (.08) pOH=1.096 pH+pOH=14 pH = 14 – pOH pH = 14 – 1.096 pH=12.90.