What is the molar solubility of Ag2CrO4?
Table of Contents
- 1 What is the molar solubility of Ag2CrO4?
- 2 What is Ag2CrO4 chemistry?
- 3 What is the solubility of Ag2CrO4 in water if the solubility product?
- 4 How does Ag2CrO4 dissociate?
- 5 What is the ratio of dissolved AgBr to solution of AgBr?
- 6 What is the solubility ratio of magnesium phosphate and magnesium ion?
What is the molar solubility of Ag2CrO4?
75 × 10 – 13 = x 3 2 . 75 × 10 – 13 3 = x 3 3 x = 2 . 75 × 10 – 13 3 . The molar solubility of Ag2CrO4 in water is 6.5 x 10-5 M.
What is the expression of KSP of Ag2CrO4?
The expression for the solubility prouct is Ksp=[Ag+]2[CrO42−]=(2S)2S=4S3.
What is Ag2CrO4 chemistry?
Silver chromate | Ag2CrO4 – PubChem.
What is the molecular weight of Ag2CrO4?
331.73 g/mol
Silver chromate/Molar mass
What is the solubility of Ag2CrO4 in water if the solubility product?
The solubility product of Ag2CrO4 is 32 × 10^-12 .
Is Ag2CrO4 ionic or molecular?
This compound is an ionic compound. The atoms present are Ag, Cr and O. The charge on Ag is +1, and the charge on CrO4 C r O 4 is -2. So, to balance the charges, 2 Ag cations and 1 CrO4 C r O 4 anion combine to form a neutral compound.
How does Ag2CrO4 dissociate?
of dissociation: Ag2CrO4 > 2Ag+ + CrO4-2 and calculate the Ksp-expr. 5.5 The solubility of Ag2CrO4 in pure water is 6.54E-5M. Show that the solubility of Ag2CrO4 in a 0.05M AgNO3 sol. is 4.48E-10M.
What is the solubility product of Ag2CrO4?
If the solubility of Ag2CrO4 is S mole/lit. Then its solubility product is: is S mole/lit. Then its solubility product is: Hence, option C is correct. Was this answer helpful?
What is the ratio of dissolved AgBr to solution of AgBr?
Ksp= [Ag+] [Br¯] 3) There is a 1:1 molar ratio between the AgBr that dissolves and Ag+that is in solution. In like manner, there is a 1:1 molar ratio between dissolved AgBr and Br¯ in solution.
What is the K sp equation for dissolving MgF2?
Solution: 1 Here’s the chemical equation for the dissolving of MgF 2 : MgF 2 (s) ⇌ Mg 2+ (aq) + 2F¯ (aq) 2 The K sp expression is this: K sp = [Mg 2+] [F¯] 2 3 Based on the stoichiometry of the chemical equation, the [F¯] is this: 4.68 x 10 -4 M 4 To calculate the K sp, do this:
What is the solubility ratio of magnesium phosphate and magnesium ion?
These is a 3:1 ratio between the concentration of the magnesium ion and the molar solubility of the magnesium phosphate. There is a 2:1 ratio between the concentation of the phosphate ion and the molar solubility of the magnesium phosphate. Therefore: