Guidelines

Which is the correct path for traveling salesman problem?

Which is the correct path for traveling salesman problem?

In the traveling salesman path problem, we are given a set of cities, traveling costs between city pairs and fixed source and destination cities. The objective is to find a minimum cost path from the source to destination visiting all cities exactly once.

How are the shortest path and traveling salesman problem similar?

They are similar, because each of then has to walk a graph and find a path in them. The shortest-path requires just a path between two points, while the traveling salesman requires a path between more points that returns to the first point.

Which statement is true about traveling salesman problem?

The only known way to verify that a provided solution is the shortest possible solution is to actually solve the entire TSP. Since it takes exponential time to solve NP, the solution cannot be checked in the real polynomial time. Hence, this problem is NP-hard, but not in NP.

READ ALSO:   How many flip flops are needed for a 3 bit Asynchronous counter?

What is the difference between Hamiltonian cycle and Travelling salesman problem?

Note the difference between Hamiltonian Cycle and TSP. The Hamiltonian cycle problem is to find if there exists a tour that visits every city exactly once. A TSP tour in the graph is 1-2-4-3-1.

Can we solve the Travelling salesman problem with Bellman form or Dijkstra’s problem?

Dijkstra’s algorithm is not applicable to the traveling salesperson problem.

What is Travelling salesperson problem explain with suitable example?

For example, consider the graph shown in the figure on the right side. A TSP tour in the graph is 1-2-4-3-1. The cost of the tour is 10+25+30+15 which is 80. The problem is a famous NP-hard problem.

How are the shortest path and traveling salesman problem given above similar How are they different?

They are similar, because each of then has to walk a graph and find a path in them. The difference is the constraint on the solution. The shortest-path requires just a path between two points, while the traveling salesman requires a path between more points that returns to the first point.