How do you calculate the resistance of 1km long copper wire?
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How do you calculate the resistance of 1km long copper wire?
Expert Answer:
- Resistance R = ρ × (L/A)
- where ρ= 1.7 × 10-8 Ω-m is resistivity of copper, L is length of wire and A is area of cross section .
- R = ( 1.7 × 10-8 × 1000 ) / ( π × 10-6 ) = 5.411 Ω
How do you find the length of a wire using resistance?
By dividing the resistance value for the entire wire by the resistance value for the 1 m length, you can estimate the overall length of the wire (in meters).
What is the resistance of a gauge 10 copper wire whose length is 10 m?
A 20-Amp circuit should never be wired using 14-gauge wire. 3. Determine the resistance of a 1-mile length of 12-gauge copper wire. Given: 1 mile = 1609 meters and diameter = 0.2117 cm….Variables Affecting Electrical Resistance.
| Material | Resistivity (ohm•meter) |
|---|---|
| Polyethylene | 108 – 109 |
| Glass | 1010 – 1014 |
| Hard Rubber | 1013 |
What is the resistance of a 5.4 m length of copper wire?
5.1×10−2Ω
How do you calculate wire length?
To calculate spring wire length per coil, you must subtract the wire diameter from the outer diameter in order to get mean diameter. Once you have calculated mean diameter, multiply it by pi (3.14); this will give you the length of wire per coil.
Should the resistance be low or high?
Answer: The resistance of an ammeter should be low. An ammeter has to be connected in series with the circuit to measure current. In case, its resistance is not very low, its inclusion in the circuit will reduce the current to be measured.
What is the resistance of a copper wire?
For example, the resistivity of a good conductor such as copper is on the order of 1.72 x 10-8 ohm metre (or 17.2 nΩm), whereas the resistivity of a poor conductor (insulator) such as air can be well over 1.5 x 1014 or 150 trillion Ωm.
What is the resistance of a 3.5 m length of copper wire?
3.3×10−2Ω
What is the resistance of copper wire?
What is the resistance of A 20.0 m long piece of 12 gauge copper?
0.104 ohms
So that’s 1.72 times 10 to the minus 8 ohm meters times 20.0 meters—length— multiplied by 4 divided by π times the diameter squared and this gives 0.104 ohms is the resistance of this piece of wire.
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