How many ways a group of 3 students can be selected from 7 men and 5 women consisting of 1 man and 2 women?
How many ways a group of 3 students can be selected from 7 men and 5 women consisting of 1 man and 2 women?
Out of 7 men, 3 men can be chosen in 7C3 ways and out of 5 women, 2 women can be chosen in 5C2 ways. Hence, the committee can be chosen in 7C3×5C2=350 ways.
How many ways can a 5 persons committee can be formed from a group of 7 men and 5 women if at least 3 men are part of the committee?
5! = 20 ways. 3! Required number of ways = (2520 x 20) = 50400.
How many committees consisting of 2 women and 3 men can be selected from a group of 6 women and 7 men?
There are 1,176 different possible committees.
How many different committees of 5 people can be formed?
After simplifying (very preferably with a scientific or graphing calculator), we get 3003. So, there are 3003 ways of picking 5 people from a group of 15. Note that the combination formula can be noted by _nCr . It is this way that you can enter it onto a graphing calculator.
How many ways a 6 member team can be formed having 3 men and 3 ladies from a group of 6 men and 7 ladies?
How many ways a 6 member team can be formed having 3 men and 3 ladies from a group of 6 men and 7 ladies? Question 4 Explanation: We have to pick 3 men from 6 available men and 3 ladies from 7 available ladies. Required number of ways = 6C3 * 7C3 = 20 * 35 = 700.
How many different committees of 5 members can be formed from 6 men and 4 ladies if each committee is to contain at least one lady?
246
Complete step-by-step answer: According to the question we have to make a committee of 5 and in each committee formed there must be at least one lady. There are 6 gentlemen and 4 ladies. Hence, the required number of committees is 246.
How many committee of size 5 consisting of 3 men and 2 women can be selected from 8 men and 6 women if a certain man must not be on the committee?
There are 525 different arrangements.
How many ways a committee of 5 members can be selected from 7 men and 5 ladies consisting of three men and two ladies?
(∵ncr=n! r! (n−r)!) Hence in a committee of 5 members selected from 6 men and 5 women consisting 3 men and 2 women is 200 ways.