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How the inductor voltage and capacitor voltage are related in series?

How the inductor voltage and capacitor voltage are related in series?

The instantaneous voltage across a pure inductor, VL “leads” the current by 90. The instantaneous voltage across a pure capacitor, VC “lags” the current by 90. Therefore, VL and VC are 180o “out-of-phase” and in opposition to each other.

How the inductor voltage and capacitive voltage are related in series LCR AC circuit?

Solution: The phasor diagram of series RLC circuit is drawn by combining the phasor diagram of resistor, inductor and capacitor. In inductor, voltage leads current by 90o so we draw VL in perpendicular to current phasor in leading direction. Similarly VC is perpendicular to current phasor in lagging direction.

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How do you find the voltage across a capacitor in a LCR circuit?

The formula of the resultant voltage is given by $ \Rightarrow V = \sqrt {{V_R}^2 + {{\left( {{V_L} – {V_C}} \right)}^2}} $ where ${V_R}$is the voltage across the resistor, ${V_C}$ is the voltage across the capacitor, ${V_L}$is the voltage across the inductor and V is the voltage for the LCR circuit.

Is it possible to use a capacitor as an inductor in series?

In case of DC steady state RLC circuit , entire voltage appears across capacitor and voltage across resistance and inductance becomes zero. Yes it is possible. During series resonance the voltage across inductor and capacitor is “Q” times the supply voltage (Q= Quality Factor) and for this reason it can also be called VOLTAGE AMPLIFICATION CIRCUIT.

Is the LCR circuit capacitive or inductive?

If XL>Xc, then tan∅>0 in this case, the voltage leads the current, and the LCR circuit is said to be an inductive circuit. 2. If XL

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What are the advantages of series LCR circuit?

Actually, series LCR circuit can provide voltage magnification. This happens at the resonant frequency where the magnitude of the voltage across an inductor (and capacitor) can go extremely high depending on the value of resistance (or current through the circuit).

Can the voltage across an inductor be greater than the source?

Yes, the voltage across an inductor (and capacitor) can be greater than the source voltage. Actually, series LCR circuit can provide voltage magnification.