How would you find a missing number in a randomized array with 1 100?

Now, sum of natural numbers from 1 to N, can be expressed as Nx(N+1)/2 . In your case N=100. Subtract the sum of the array from Nx(N+1)/2 , where N=100. That is the missing number.

How do you tell the max frequency of the element in the given array?

Algorithm

1. Start.
2. Declare the array.
3. Initialize the array.
4. Call the function that will return the most occurring element.
5. Declare two for loops.
6. The first for loop will hold each element.
7. The second for loop will check for duplicate elements.
8. If duplicate elements found, increment the count.

How do you find the number of occurrences of an element in an array?

Java Program to Count the Number of Occurrence of an Element in…

1. import java.util.Scanner;
2. public class Count_Occurrence.
3. {
4. public static void main(String[] args)
5. {
6. int n, x, count = 0, i = 0;
7. Scanner s = new Scanner(System. in);
8. System. out. print(“Enter no. of elements you want in array:”);

How do you find a number in an array which is repeated?

Algorithm

1. Declare and initialize an array.
2. Duplicate elements can be found using two loops. The outer loop will iterate through the array from 0 to length of the array. The outer loop will select an element.
3. If a match is found which means the duplicate element is found then, display the element.

How do you find the missing number in a integer array of 1 to 100 in C#?

Algorithm: step1: XOR all the array elements, let the result of XOR be X1. step2: XOR all numbers from 1 to n, let XOR be X2. step3: XOR of X1 and X2 gives the missing number.

How do you find the missing number in a integer array of 1 to 100 using python?

Algorithm

1. Step 1: Create an empty array for missing items.
2. Step 2: Loop over the elements within the range of the first and last element of the array.
3. Step 3: Compare the loop variable with the given array if the value is not present append it to the missing array.
4. Note: The array must be sorted for this to work.
5. Output:

How do you count occurrences of each element in an array Java?

Algorithm

1. STEP 1: START.
2. STEP 2: INITIALIZE arr[] ={1, 2, 8, 3, 2, 2, 2, 5, 1 }.
3. STEP 3: CREATE fr[] of arr[] length.
4. STEP 4: SET visited = -1.
5. STEP 5: REPEAT STEP 6 to STEP 9 for(i=0;i
6. STEP 6: SET count = 1.
7. STEP 7: REPEAT STEP 8 for(j=i+1;j
8. STEP 8: if(arr[i]==arr[j]) then. count++

How do you find the first repeated element in an array?

Find the first repeating element in an array of integers

1. Copy the given array to an auxiliary array temp[].
2. Sort the temp array using a O(nLogn) time sorting algorithm.
3. Scan the input array from left to right. For every element, count its occurrences in temp[] using binary search.