Is it possible to have a voltage drop across the energy storage element greater than the supply?

Answer Expert Verified Yes, the voltage drop across the inductor or the capacitor in a series LCR circuit can be greater than the applied voltage of the AC source. This is because the voltage drops across these two elements are not phase voltages.

How do you calculate voltage in an RLC circuit?

For a series RLC circuit, and impedance triangle can be drawn by dividing each side of the voltage triangle by its current, I. The voltage drop across the resistive element is equal to I*R, the voltage across the two reactive elements is I*X = I*XL – I*XC while the source voltage is equal to I*Z.

What is the phase difference between the instantaneous current and the instantaneous resistor voltage?

Instantaneous values of alternating voltage and current The phase difference of the current is zero; the current amplitude Im has been calculated above.

What is the instantaneous value of current through the circuit when the voltage across the inductor is zero?

= 0
It only relates the emf produced across the inductor to changes in current because if the flow of inductor current is constant and not changing such as in a steady state DC current, then the induced emf voltage will be zero because the instantaneous rate of current change is zero, di/dt = 0.

What is instantaneous voltage?

Instantaneous Voltage. The EMF induced in the coil at any instant of time depends upon the rate or speed at which the coil cuts the lines of magnetic flux between the poles and this is dependant upon the angle of rotation, Theta ( θ ) of the generating device.

How is time related to the instantaneous voltage and current?

At a particular instant, the current is given by the time rate of change in the amount of charge. For a constant applied voltage (DC), the current is constant with respect to time since the charges move uniformly. But for AC circuits, the instantaneous current changes with time.

Can the voltage drop across inductor and capacitor in a series LCR circuit be greater than the applied voltage justify your answer?

Yes, the voltages dros the inductor or the capacitor in a series circuit can be greater than the applied voltage are not in phase and they cannot be added like ordinary numbers.

Why can’t we calculate net voltage in LCR circuit?

Here, in an LCR circuit, when the current is maximum, it will be maximum (and of the same value to maintain the continuity of current) in all the three components, i.e, resistor R, conductor C and inductor I. Now, why can’t we calculate the net voltage by simply adding the voltage drop or raise normally (±).

What is the maximum current in RLC resonant circuit?

In this series connected RLC resonant circuit the maximum current occurs at the resonance condition ω L = 1 / ω C In this case, the impedance of the inductor-capacitor series connection becomes zero because the voltage drops over the capacitor and the inductor have opposite phase summing up to zero voltage.

What is the current through the RLC connection?

At resonance, the current through the RLC connection is given by the amplitudes of the voltage drops over the capacitance and the inductance, V C and V L, can easily become much larger than the applied voltage V 0. This is a common phenomenon in resonant circuits which can lead to the destruction (breakdown) of the circuit elements.

What is the impedance of inductor-capacitor series connection?

Inductors and capacitor have voltage phasors with angles: In short, the angles are important and because part of the phasor sum. In this case, the impedance of the inductor-capacitor series connection becomes zero because the voltage drops over the capacitor and the inductor have opposite phase summing up to zero voltage.