What is the momentum of a 10 kg object moving at 3 m s?
Table of Contents
- 1 What is the momentum of a 10 kg object moving at 3 m s?
- 2 What is the momentum of a body of mass 10kg and velocity 5m S?
- 3 What is the momentum of an object of mass m moving with a velocity v?
- 4 What force would be needed to make a 10 kg bowling ball accelerate down the alleyway with an acceleration of 3 m s2?
- 5 What is the momentum of a body of mass 10 kg if the body is at rest?
- 6 How do you find momentum in Class 9?
What is the momentum of a 10 kg object moving at 3 m s?
Its momentum is 30 kg m/s .
What is the momentum of a body of mass 10kg and velocity 5m S?
Answer: The linear momentum of a body of mass 10 kg moving with velocity 5 m/sec is 50 kg m/s.
How do you calculate momentum in kg MS?
The Momentum Calculator uses the formula p=mv, or momentum (p) is equal to mass (m) times velocity (v).
What is the momentum of an object of mass m moving with a velocity v?
The momentum, p of an object is defined as the product of its mass, m and velocity, V. Momentum = Mass x Velocity. That is, p = mv.
What force would be needed to make a 10 kg bowling ball accelerate down the alleyway with an acceleration of 3 m s2?
Given a mass of 10kg and an acceleration of 3ms2 , we can calculate the net force on the bowling ball from the above equation. Therefore, 30N of force is required to accelerate the bowling ball down the alleyway at a rate of 3ms2 .
What is the momentum of an 8.2 kg bowling ball rolling at 1.2 m s?
Physics the fourth
| A | B |
|---|---|
| What is the momentum of an eight kg bowling ball rolling at 2 m/s? | 8 kg x 2 m/s=16 kg x m/s |
| If the bowling ball rolls into a pillow and stops in .5 s, calculate the average force exerted on the pillow. | F=deltamv/t=16kg x m/s/0.5 s=32 N |
| What average force does the pillow exert on the bowling ball. | same |
What is the momentum of a body of mass 10 kg if the body is at rest?
Therefore, the momentum of a body of mass kg if the body is at rest is zero.
How do you find momentum in Class 9?
The initial and final momentum of the object will be, p1 = mu and p2 = mv respectively. The change in momentum = m × (v – u). Here a = [(v – u)t (v – u) t ] is the acceleration, which is the rate of change of velocity. The quantity, k is a constant of proportionality.