How many 7 digit combinations are there with 10 numbers?

In this case you have all ten digits [0,1,2,3,4,5,6,7,8,9] at your disposal. Assuming repetition is allowed, you can have 7-digit numbers from 1,000,000 to 9,999,999 which is a total of 9,000,000 7-digit numbers. These are all the possible 7-digit numbers. In general, there are 9 × 10^(n-1) possible n-digit numbers.

How many 7 digit integers can be formed?

So total number of 7 digit numbers=9999999 – 1000000+1). Out of 9000000 numbers, 4500000 are having the sum of digits as even and the remaining 4500000 are having the sum of digits as odd. Every alternate number has its sum of digits even and odd. There are 9000000 seven digit numbers.

How many two digit numbers are there with sum of digits equal to 10?

Description for Correct answer: Let the two-digit number be 10x + y. Therefore, Required number is 73.

How many 7 digit numbers can be formed by using the numbers 1 2 and/or 3?

We know that the factorial can be written by the formula n! =n×(n−1)! Therefore, the number of different seven-digit numbers that can be written using only three digits 1,2 and 3 is 672. Thus, option (A) is the correct answer.

How many 7 digit numbers are there with no digits repeated?

There are 9 digits you can have for the first digit (can’t have 0). There are then 9 more for the second (all except the first one). Similarly there are 8 for the third, 7 for the 4th, etc… So the total would be 9*9*8*7*6*5*4 = 544,320 7 digit numbers without repeated digits.

How many 4 digit numbers ABCD exist such that A is odd?

480. Hint: Take each digit separate and look for the values which satisfy the conditions. Note: Similar problems including combination of conditions can be asked. In that case, the above method is best suited.

How many numbers greater than 3000 can be formed?

1380 positive integers can be formed which are greater than 3000.

How many two digit whole numbers are exactly 7 times the sum of their digits?

2 Answers By Expert Tutors The number is 63. The sum of the digits is 9. 9 x 7 = 63.

How many numbers are there between 99 and 999?

the correct answer is 162.

How many seven digit numbers can be made from the digits 1 to 7 if repetition is allowed?

The numbers beginning with 0 won’t be 7 digit numbers, they would be 6 digit numbers. No. of such numbers are: 6!/(3!

How many 7 digit numbers are there having the digit 3 three times and the digit 0 four times )?

Latest Book Aptitude Question SOLUTION: How many 7 digit numbers are there having the digit 3 three times and the digit 0 four times. Ans :15.