What is the total effective resistance in the circuit if 3 resistance are connected in parallel?

P. Q and R are three resistances. When P,Q and R are connected in parallel, their total resistance is 3Ω. When P and Q are connected in parallel their total resistance is 10/3 Ω.

What is the effective resistance of the three resistors?

The effective resistance of three resistors connected in parallel is 60/47 Ω. When one wire breaks, the effective resistance becomes 15/8 ohms.

What will be the effective resistance if three resistors 2 ohms 3 ohms and 4 ohms are connected in series?

From the question, the correct answer is 9.

When three equal resistance are connected in parallel the effective resistance is 1 by 3 ohm if all are connected in series the effective resistance is?

The effective resistance of three equal resistances, each of resistance r, connected in parallel, is. Then 1R=1r+1r+1r=3r.

What is the total resistance of a circuit consisting of three 30 ohm resistors in parallel?

If a series–parallel circuit has all 30-ohm resistors, the total resistance when r1 is in series with a parallel circuit consisting of r2 and r3 is 45ohms.

What is the effective resistance of the circuit?

Hint: Effective Resistance refers to the resistance between two points in any electric network in any electric circuit. The total resistance of all the resistors used in any electric circuit where the resistor is two or more is the effective resistance of the circuit.

How do you find the effective resistance of a circuit?

For a circuit with resistances R1 and R2 in series or in parallel as in Figure 2, the effective resistance can be calculated by using the following rules. Rab = R1 + R2. Proof. Let Iab be the current from a to b.

What is total resistance in a parallel circuit?

The sum of the currents through each path is equal to the total current that flows from the source. You can find total resistance in a Parallel circuit with the following formula: 1/Rt = 1/R1 + 1/R2 + 1/R3 +… Rt = R (t)otal. If one of the parallel paths is broken, current will continue to flow in all the other paths.

How will you combine three 2 Ω resistors to have an equivalent resistance of 3 Ω?

Answer: Two in parallel one in series. And next we add the third resistor in series, when in series resistors are simply added, therefore: 1 ohm (obtained earlier) + 2 ohm (third resistor) = 3 ohm !

What will be the equivalent resistance if three resistors of resistances 3 Ohm 4 Ohm and 5 ohm are connected in parallel?

=47/60.