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How do you find the largest remainder of a number?

How do you find the largest remainder of a number?

October 16, 2015. The result of dividing a number n by a divisor d is a quotient q and a remainder r. Given a fixed n and a divisor d in the range 1 ≤ d < n, find the divisor that produces the largest possible remainder. For instance, given n = 20 and 1 ≤ d < 10, the largest remainder is 6 when the divisor d is 7.

What is the smallest number which leaves 9 remainder when divided by 12 18 and 21?

Step-by-step explanation: 12= 2 x 2 x 318= 2 x 3 x 3.So LCM of 12, 18 =2 x 3 x 2 x 3= 36. Therefore 36 + 9= 45, is the smallest number, when divided by 12 or 18 will give a remainder of -9.

Which smallest number will have 5 as reminder in every case when divided by 8 12 18 24?

Add 5 to 72 to get 77 as the answer.

What is the largest possible remainder if a number is divided by 8?

When 8 is used as a divisor for a number such that a remainder is obtained, the remainder must always be greater than zero but less than 8.

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What is the smallest number which when divided by 12 and 16 gives remainder 5 and 9?

The smallest number, which when divided by 12 and 16 leaves remaining 5 and 9 respectively, is : – GKToday. = 48 – 7 = 41. Hence option [C] is correct answer.

What is the smallest number which when divided by 13 and 15 leaves 11 and 13 as a reminder respectively?

The correct ans is 1068. Hope this help u.

What is a remainder of a number?

In arithmetic, the remainder is the integer “left over” after dividing one integer by another to produce an integer quotient (integer division). Alternatively, a remainder is also what is left after subtracting one number from another, although this is more precisely called the difference.

What is the smallest possible number which when divided by 12 15 20 and 54 leaves a remainder 4 in each case?

Answer: LCM of 12, 15, 20, and 54 is 540. Explanation: The LCM of four non-zero integers, a(12), b(15), c(20), and d(54), is the smallest positive integer m(540) that is divisible by a(12), b(15), c(20), and d(54) without any remainder.

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What is the smallest number to divide 24 and 36?

Step 3: The smallest common multiple of 24 and 36 is 72.