How many grams of O2 are produced from 3 moles KClO3?
Table of Contents
- 1 How many grams of O2 are produced from 3 moles KClO3?
- 2 How much oxygen gas can be produced by the decomposition of 200 grams of KClO3?
- 3 What is the volume of oxygen liberated when 49 gm of potassium chlorate is decomposed at STP?
- 4 How much oxygen O2 is produced by the decomposition of 25 g of HGO?
- 5 What is the balanced equation for the decomposition of potassium chlorate?
- 6 How many moles of oxygen are produced when potassium chlorate decomposes?
How many grams of O2 are produced from 3 moles KClO3?
110.88 g of oxygen is produced.
How much oxygen gas can be produced by the decomposition of 200 grams of KClO3?
This ratio times the original 200 grams of the compound, gives us 78.34 grams of oxygen produced. 200g KClO3 will produce: 200g KClO3 * 48gO2 / 122.6g KClO3 = 78.3g O2 produced.
How many grams of oxygen are produced in the decomposition of 5 grams of potassium chlorate?
We can see that from two moles of potassium chlorate, three moles of oxygen is produced. Thus, we can conclude that the mass of oxygen produced in the complete decomposition of 5 g of $KCl{O_3}$ will be 1.9684 g.
How much oxygen can be produced from the decomposition of KClO3?
This tells us that for every 2 moles of potassium chlorate that are decomposed, then 3 moles of oxygen gas is produced.
What is the volume of oxygen liberated when 49 gm of potassium chlorate is decomposed at STP?
×12.25 =3.36 L.
How much oxygen O2 is produced by the decomposition of 25 g of HGO?
Hence, 9.79 g of oxygen is produced.
How many moles of O2 will be formed from 1.65 moles?
Stoichiometry Worksheet and Key2 KClO3 2 KCl + 3 O21. How many moles of O2 will be formed from 1.65 moles of KClO3? 1.65 mol KClO33mol O2= 2.475 mol O22 mol KClO32.
How many moles of O2 can be produced by letting 12.0 mol of KClO3 react in the following equation?
How many moles of O2 can be produced by letting 12.00 moles of KClO3 react? The KClO3 / O2 molar ratio is 2/3. 2 mol KClO3 / 3 mol. O2 = 12.00 mol KClO3 / x = 18.00 mol.
What is the balanced equation for the decomposition of potassium chlorate?
Potassium chlorate, KClO3, will decompose upon heating to form potassium chloride, KCl, and oxygen gas, O2, according to the following balanced chemical equation 2KClO3 (s] Δaa − → 2KCl(s] +3O2 (g] ↑ The reaction will produce 3 moles of oxygen gas for every 2 moles of potassium chlorate that decompose.
How many moles of oxygen are produced when potassium chlorate decomposes?
The reaction will produce 3 moles of oxygen gas for every 2 moles of potassium chlorate that decompose. This will be the theoretical yield of the reaction, i.e. what you get when the reaction has a 100\% yield.
How do you calculate the amount of oxygen produced from KClO3?
To determine the amount of oxygen that is being produced in the reaction from the given amount of the starting material, we need the balanced chemical reaction to relate the substances and the molar masses of the substances involved. The molar mass of KClO3 is 122.55 g/mol and O2 is 32 g/mol. We do as follows:
What is the reaction between potassium chlorate and KClO3?
Potassium chlorate, KClO3, will decompose upon heating to form potassium chloride, KCl, and oxygen gas, O2, according to the following balanced chemical equation The reaction will produce 3 moles of oxygen gas for every 2 moles of potassium chlorate that decompose.