What happens when potassium hydroxide reacts with Sulphuric acid?

Potassium hydroxide reacts with sulfuric acid. Potassium sulfate and water are formed in the reaction. This means that: the word equation is: potassium hydroxide + sulfuric acid → potassium sulfate + water.

How much sulfuric acid is needed to neutralize potassium hydroxide?

Nothing but grams can be expressed in amu also. For 98 grams of sulphuric acid 2 moles of potassium hydroxide is sufficient to neutralize.

How many grams of Sulphuric acid will be needed to react completely with a solution containing 10.6 g sodium carbonate?

10.6 grams is approximately 0.10 moles. So you would need about 0.10 moles of sulfuric acid. That converts to about 9.80 grams.

What type of reaction is sulfuric acid potassium hydroxide -> potassium sulfate water?

Explanation: This is an example of a double replacement (double displacement) reaction. This type of double replacement is called a neutralization reaction since an acid and a base react and one of the products is water.

How is potassium sulfate formed?

Preparation. It is made by reacting potassium hydroxide and sulfuric acid. It can also be made by reacting potassium chloride with sulfuric acid. It can also be made by reacting sulfur dioxide, oxygen, and potassium chloride with some water.

How many grams of H2SO4 are needed to neutralize completely?

One mole of H2SO4 (98 grams) will neutralize two moles on NaOH (40 grams per mole).

How many grams of HCL will be needed to react completely with a solution containing 15 g of Naoh?

×69.6=116.8 gm.

What is a double displacement reaction?

A double-replacement (or double-displacement) reaction is a reaction in which the positive and negative ions of two ionic compounds exchange places to form two new compounds. Double-replacement reactions can form precipitates, gases, or molecular compounds.