What is the minimum rank for IIT Computer Science?
What is the minimum rank for IIT Computer Science?
JoSAA 2020 IIT Cutoff for CSE: Opening & Closing Ranks for Round-5
| Institute | Opening Rank | Closing Rank |
|---|---|---|
| Indian Institute of Technology Kanpur | 111 | 239 |
| Indian Institute of Technology Kharagpur | 180 | 293 |
| Indian Institute of Technology Madras | 49 | 158 |
| Indian Institute of Technology Mandi | 1927 | 2553 |
What is the rank of CS in IIT Roorkee?
A. As per IIT Roorkee 1st cut off 2021, Computer Science and Engineering with a closing cut off rank of 414 for All India General candidates became the most competitive BTech specialisation this year.
What is the ranking of Indian Institute of Technology Roorkee?
Indian Institute of Technology Roorkee (IITR) is one of the top Public universities in Roorkee, India. It is ranked #=400 in QS Global World Rankings 2022. QS World University Rankings #=400
What is it like to study at IIT Roorkee?
The institute has also been said to be a trendsetter in the field of education and research covering areas like science, technology, and engineering. IIT Roorkee is located in the Haridwar district of Uttarakhand and is among the biggest engineering institutions having the largest academic unit. The main campus in Roorkee has an area of 365 acres.
Who is the founder of IIT Roorkee?
The college was founded in 1847 by Sir James Thomason and later converted to an IIT in the year 2001. Today, this institute is regarded as Institution of National Importance as the other IITs in India. Indian Institute of Technology – Roorkee is also among the top institutes that provide higher technical education to students.
What is the cut off for IIT Roorkee JEE Advanced 2020?
IIT Roorkee JEE Advanced 2020 Cutoff Course Name Category Male Female Biotechnology OBC 3790 7442 Biotechnology EWS 1637 2572 Biotechnology General 7675 10894 Biotechnology SC 2070 2683