When 8 g of hydrogen and 8 g of oxygen is forced to combine then the amount of water formed is?

2 Answers. ≈70 g H2O will produced from 8 g H2 .

What is the limiting reactant of hydrogen and oxygen?

In this example, hydrogen is the limiting reagent and oxygen is the excess reagent. The amount of product formed is limited by the amount of hydrogen. In a chemical reaction, reactants that are not used up when the reaction is finished are called excess reagents.

What is the limiting reagent if 2 grams of H2 react with 8 grams of O2 to form water?

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product. By Stoichiometry of the reaction: 1 mole of oxygen gas produces 2 moles of water molecule.

When 1 g of hydrogen reacts with 8 g of oxygen 9 g of water what will form?

Explanation: According to the law of Definite proportions one gram of hydrogen will always react with 8 gram of oxygen to form 9 gram of water and the rest will gram of Oxygen will be left untreated.

What is the total mass of water formed when 8 grams of hydrogen reacts completely with?

Answer: The total mass in grams of water formed when 8.00 grams of hydrogen reacts completely with excess oxygen is 71.5 g.

What mass of oxygen is required to react completely with 3g of hydrogen gas?

24g
For every 1g of hydrogen = 8g of oxygen. Hence, 24g of oxygen would be required for the complete reaction with 3g of hydrogen gas.

Is oxygen always the limiting reactant?

Thus, two moles of Mg require only ONE mole of O2. Four moles of oxygen will remain unreacted. Therefore, oxygen is the excess reagent, and Mg is the limiting reagent.

When 3g of H2 react with 29g of O2 to form water O2 is the limiting reagent?

3g of hydrogen will be the limiting reagent. As the given amount of O2 is more than required therefore O2 is excess reagent and H2 is limiting reagent.

When 1g of hydrogen is combined with 8g of oxygen 9g of water is produced what would be the mass of oxygen required to react with 4g of hydrogen?

It is given that the ratio of hydrogen and oxygen by mass to form water is 1:8. Then, the mass of oxygen gas required to react completely with 1g of hydrogen gas is 8g. Therefore, the mass of oxygen gas required to react completely with 3g of hydrogen gas is 8 × 3g = 24 g.

What is the amount of water produced when 8g of hydrogen is reacted with 32g of oxygen *?

What is the amount of water produced when 8g of hydrogen is reacted with 32g of oxygen? Clarification: The chemical equation of water formation is 2H2 + O2 → 2H2O. Though we have 8g of hydrogen, here oxygen is the limiting reagent. So the only 4g of hydrogen can be used to produce water i.e. 36g of water.

What mass of water is formed?

Water has a molar mass of 18 g/mol . So, 24mol ⋅18 g/mol =432 g of H2O was produced.

What is the limiting reactant of hydrogen and oxygen gas?

The reaction of hydrogen gas and oxygen gas to make water is as follows: We can calculate the amount of product (water) that each reactant will make, given our moles above, and whichever makes lesser moles of product is our limiting reactant. As you can see above, oxygen gas is the limiting reactant.

How many grams of hydrogen gas react with 32 grams of oxygen?

4 grams of hydrogen gas reacts with 32 grams of oxygen gas to yield 36 grams of water. Oxygen gas is insufficient since it is only 4 grams.

How do you find the limiting reagent of a reaction?

This calculator will determine the limiting reagent of a reaction. To calculate the limiting reagent, enter an equation of a chemical reaction and press the Start button. The reactants and products, along with their coefficients will appear above. Enter any known value for each reactant.

What is the limiting reagent for C3H8 and O2?

Conclusion: for every 3.11 moles of C3H8 you will need 15 moles of O2, but you don’t have that when we look at the original equation. So O2 is the limiting reagent. If you would like more practice, click “Extra Practice”!