How do you find the moment of inertia of a disk about diameter?

1. 6 I. B.
2. 4 I. C.
3. 2 I. D.
4. 6 I. Moment of inertia of a disc about an axis passing through center and perpendicular to plane of the disc=21​MR2. Thus moment of inertia about a diameter of the disc=21​×21​MR2=41​MR2=I. ⟹MR2=4I. Using parallel axis theorem, Id​=ICM​+Md2=21​MR2+MR2=23​MR2=6I. Was this answer helpful? Similar questions.

What is the expression for the moment of inertia of a circular disc of mass M and radius R about its diameter?

The moment of inertia of a uniform circular disc of mass M and radius R about any of its diameters is 1/4 MR^(2).

What formula is used to find the theoretical moment of inertia for the disk rotated about its diameter?

In integral form the moment of inertia is I=∫r2dm I = ∫ r 2 d m . Moment of inertia is larger when an object’s mass is farther from the axis of rotation. It is possible to find the moment of inertia of an object about a new axis of rotation once it is known for a parallel axis.

What is moment of inertia of a ring and disc about its diameter?

Thus the moment of inertia of the ring about any of its diameter is MR22.

What is the moment of inertia of a circular section Mcq answer?

Explanation: The moment of inertia of a circular section is πD4/64.

What is the moment of inertia of a circular ring?

The moment of inertia of a circular ring about an axis perpendicular to its plane passing through its centre is equal to $M{{R}^{2}}$, where M is the mass of the ring and R is the radius of the ring. Hence, $I=M{{R}^{2}}$.

How do you find the moment of inertia of a hollow tube?

Explanation:

1. Moment of inertia of cylinder is IC=12MR2.
2. The moment of inertia of the removed part is Ih=12ma2.
3. Volume of the cylinder is VC=πr2L.
4. The volume of the “hole” vh=πa2L.
5. Ih=12⋅a2MR2⋅a2=12a4R2M.