How many ways are there for 5 men and 8 women to stand in a line so that no two men stand next to each other?

There is a similar one to it that has not been assigned and has an answer in the back of the textbook. It reads: How many ways are there for 8 men and 5 women to stand in a line so that no two women stand next to each other? The answer is 609638400, but no matter what I try I cannot reach that number.

How many ways are there for five men and five women to stand alternatively?

Since there are 5 men, there will be 5 gaps where 5 women can sit in 5!= 120 ways. Hence, total number of arrangements of sitting of 5 men and 5 women with no two women can sit together is 24*120= 2880.

How many ways are there for four men and five women to stand in a line so that a all men stand together?

ways therefore 720 x 24 =17280 ways.

How many arrangements are possible if any individual can stand in any position for 8 women and 6 men are standing in a line?

There are 9 places so the 6 men can be arranged in the 9 places in 9P6 ways. After this arrangement, the 8 women can be arranged in 8! ways. ∴ Total number of arrangements = (9P6) × 8!

How many ways are there for 10 women and six men to stand in a line so that no two men stand next to each other?

How many possible ways are there to arrange ten women in a row? It will be 10P10=10! =3628800. A man can be inserted in any one of the eleven positions marked off with a ‘*’, and this will ensure no two men stand next to each other.

How many ways are there for three men and six women to stand in a line A so that all women stand together?

Total ways are 17280 I need explaination how?

How many ways can 5 men and 5 women be seated in a round table of each woman is to be between 2 men?

Determine the number of ways such that 5 men and 5 women be seated at a round table if no two women are seated together. ways. Now, the 5 men can be seated in the remaining seats in 5! or 120 ways. Therefore the total number of ways in this case will be (10-1)!

How many ways are there for 10 women and 6 men to stand in a line from left to right so that?

It will be 10P10=10! =3628800.

How many distinct permutations are there in the word Mississippi?

34650
Hence the total number of possible permutations in the word MISSISSIPPI are 34650.

How many ways are there for 10 men and 6 women to stand in a line?

Answer Expert Verified 3628800. 11P6=11×10×9×8×7×6=332640.