Why the series field is short circuit at the time of starting in differential compound motor?
Table of Contents
- 1 Why the series field is short circuit at the time of starting in differential compound motor?
- 2 What happens when DC motor is short circuited?
- 3 What is the effect on speed of DC compound motor when the series field winding is shorted?
- 4 Why does Series motor start with load?
- 5 How can you tell if a motor is short circuited?
- 6 What happens when a motor short circuits?
- 7 What will happen when the field of decision motor gets opened while the motor is running?
- 8 What will happen when the field of a DC shunt motor gets opened while the motor is running Why?
Why the series field is short circuit at the time of starting in differential compound motor?
In starting a differential compound motor the series field should be short-circuited, as the large starting current passing through the series field may be sufficiently large to overbalance the shunt field ampere-turns and cause the motor to start in the wrong direction.
What happens when DC motor is short circuited?
The winding will burn out, as shorting will result in high amounts of current flowing through it. The field produced by the poles will die out. The generated voltage will reduce significantly as the flux is very low.
What is the effect on speed of DC compound motor when the series field winding is shorted?
In a cumulative compound DC motor with rated voltage applied with rated load, if the series winding part is shorted, then speed will be: less than full speed.
What will happen if field winding of running DC motor suddenly gets open circuited?
If field winding is disconnected accidentally, the speed would dangerously increase in order to maintain the back emf of the motor. For a constant back emf, flux is inversely proportional to the speed of the motor.
What would happen if the field of DC shunt motor is opened?
If the shunt field opens under a no-load condition, the armature current will once again increase. Because very little torque is needed to overcome the windage and friction, the motor would continually increase in speed. Under these conditions, the motor will act as a series DC motor.
Why does Series motor start with load?
At the starting of the motor there is no back emf, so large current current flows cause high starting torque. This starting torque leads to very fast acceleration of motor if shaft is not connected to any load. This fast acceleration cause motor to damage. So series motor are always started with load.
How can you tell if a motor is short circuited?
You should test the windings for a “short to ground” in the circuit and open or shorts in the windings. To test your motor for short to ground, you’ll need to set the multimeter to ohms and disconnect the motor from its power source. Then inspect each wire and look for infinite readings.
What happens when a motor short circuits?
During a short circuit condition the system voltage will decay. A stable voltage supply no longer exists. The rotating magnetic field in the rotor will attempt to support the reduced voltage condition by becoming a power source. The motor is now providing additional current into the faulted electrical system.
Is it possible to work a compound motor as series or shunt motor explain?
Thanks to the presence of the features of these two motors in compound DC motors, they can operate even at no load. they can run at some speed within the limits. As a result, a compound motor can be used for approximately all the applications where both series and shunt motor combined can be used.
What are the advantages and disadvantages of a DC compound motor?
As a series DC motor can destroy itself due to high speed at no load. On the other hand, a compound DC motor can be used even at no load. It will run at some speed within the limits. Therefore, compound DC motor can be used for almost all the applications where both series and shunt motor combined can be used.
What will happen when the field of decision motor gets opened while the motor is running?
WHY: we know that E=K*phi*w in DC machines, so when the field is open or if=0, the generated flux (phi) is going to be zero, and for the given E, the speed is derived from E/0, so, the developed speed would be infinity. So, due to motor inertia the motor speeds up.
What will happen when the field of a DC shunt motor gets opened while the motor is running Why?
4. What will be the effect of opening of field of a DC shunt motor while motor is running? Explanation: In a DC shunt motor if supply for the field winding is cut down, the speed would dangerously increase in order to maintain the back emf of the motor.