How many natural numbers less than 1000 have the sum of their digits equal to 5?

There are thus in all 21 natural numbers <1000 whose digits sum up to 5, viz. (in increasing order) 5, 14, 23, 32, 41, 50, 104, 113, 122, 131, 140, 203, 212, 221, 230, 302, 311, 320, 401, 410, 500.

How many positive integers less than 1000 have sum of their digits as?

I think correct answer is 28.

What is the sum of all digits that appear from 1 to 1000?

500500
Examples Using Sum of Integers Formula Answer: Sum of integers from 1 to 1000 is 500500.

Can you find the number of digits for counting numbers from 1 to 1000?

Now let us look at the numbers from 1 to 1000. To write all these numbers down, we need to use 9 + 180 + 2700 + 4 = 2893 digits to accommodate the 9 single-digit numbers, the 90 double-digit numbers, the 900 triple-digit numbers and the number 1000.

How many numbers below 10,000 exist such that the sum of the digits of the number is 5?

Basically this arrangements will give us all numbers less than 10,000 in which sum of the digits (sum of 5 d’s=5) equals 5. Hence the answer is . Answer: C (56).

How many natural numbers have their cubes less than 10,000?

from 1 to 21… numbers have cubes less than 10000.

How many positive integer less than 1000000 have the sum of their digits equal to 19?

The answer will be 30492.

How many integers between 1 and 1000000 have the sum of their digits equal to 18?

25927
Hence, the number of integers between 1 and 1000000 having the sum of the digits equals to 18 is 25927 which is option (b).

What is the sum of all the numbers from 1 to 10000?

The sum of all appearing digits therefore is 10000⋅4⋅4.5=180000.

How do you count the number of digits?

Logic to count number of digits in an integer

1. Input a number from user.
2. Initialize another variable to store total digits say digit = 0 .
3. If num > 0 then increment count by 1 i.e. count++ .
4. Divide num by 10 to remove last digit of the given number i.e. num = num / 10 .
5. Repeat step 3 to 4 till num > 0 or num !=