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What volume of oxygen is required for the complete combustion of 5 cm cube of c2h to?

What volume of oxygen is required for the complete combustion of 5 cm cube of c2h to?

5=12.5, so the answer is 12.5cm.

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What will be the volume of O2 gas at STP which is required for complete combustion of 7.8 gram acetylene?

According to reaction, At STP; 1 mole of acetylene that is 22.4L require 5/2 moles of oxygen that is 52×22.4 = 56L for complete combustion.

What volume of oxygen at STP is required to effect complete combustion of 200 ml of acetylene and what would be the volume of carbon dioxide formed?

Some Basic Concepts of Chemistry. What volume of oxygen at STP is required to affect complete combustion of 200 cm3 of acetylene and what would be the volume of carbondioxide formed? Thus volume of O2 required = 500 cm3 at S.T.P. According to Gay Lussac’s law of gaseous volumes.

What is the volume of oxygen needed for the complete combustion of 1 Litre of methane if both the volumes are measured at same pressures and temperatures?

Thus for 1 mole methane we need 2 mole of oxygen for complete combustion. Hence 0.5 moles of oxygen will occupy 22.4 L x 0.5 = 11.2 L.

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What is the volume of oxygen required for complete combustion of a mixture of 5 cc of CH 4 and 5 cc of C 2 H 4?

The volume of oxygen required for complete combustion of a mixture of 5 cc of methane (CH4) and 5 cc of ethylene (C2H4) is. 1.5 cc. 2.

What is the volume of oxygen?

Oxygen – Weight and Volume Equivalents

Weight of Liquid or Gas Volume of Gas at 70°F (21°C) and 1 atm
lb kg cf
2.516 1.141 30.39
9.524 4.320 115.05
82.78 37.548 1000.00

How much volume of oxygen will be required for combustion of 40 ml of c2h2?

So for complete combustion of 40 ml of acetylene 100 ml of oxygen are required and 80 ml of CO2 is formed.

What volume of oxygen at STP is needed to cause the complete combustion of 200 ml of C2H2?

1 mole of acetylene requires 2.5 moles of oxygen for complete combustion. At NTP, 22.4 liters of acetylene requires = 2.5 x 22.4 L of oxygen. So 200 ml of acetylene at NTP requires = 0.2 / 22.4 x 2.5 x 22.4 l of O2 = 0.5 L =500 ml.

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What volume of oxygen at STP is needed to cause complete combustion of 200 ml of methane?

∴ 200 mL of C2H2 at N.T.P form CO2=2×200 mL = 400 mL.

How many liters of O2 at STP are needed to complete the combustion of 39 grams of liquid benzene?

Explanation: Hence 84 litres of O2 at STP are needed to complete the combustion of 39g of liquid benzene.