How many 5 card hands can be dealt from a standard 52 card deck if that hand has exactly two aces?
How many 5 card hands can be dealt from a standard 52 card deck if that hand has exactly two aces?
Explanation: There are 6 choices for the 2 Aces based on 4 suits in a standard deck: Clubs, Hearts, Diamonds, Spades. For each of these choices there are 4 choices for the 3 Kings (basically one choice for each suit not included). This gives a combination of 6×4=24 possible hands.
How many 5 card hand can be formed from a deck of 52 cards?
2,598,960
First, count the number of five-card hands that can be dealt from a standard deck of 52 cards. We did this previously, and found that there are 2,598,960 distinct poker hands. Next, count the number of ways that five cards can be dealt to produce one pair.
What is the probability of a jack in a deck of cards?
Find the probability of: In a playing card there are 52 cards. Number of favourable outcomes i.e. ‘2’ of spades is 1 out of 52 cards. Number of favourable outcomes i.e. ‘a jack’ is 4 out of 52 cards.
What is the number of favourable outcomes in a deck of cards?
Number of favourable outcomes i.e. ‘a jack’ is 4 out of 52 cards. Number of favourable outcomes i.e. ‘a king of red colour’ is 2 out of 52 cards. Number of favourable outcomes i.e. ‘a card of diamond’ is 13 out of 52 cards. Total number of king is 4 out of 52 cards.
How many face cards are there in a deck of 52 cards?
The card in each suit, are ace, king, queen, jack or knaves, 10, 9, 8, 7, 6, 5, 4, 3 and 2. King, Queen and Jack (or Knaves) are face cards. So, there are 12 face cards in the deck of 52 playing cards. Worked-out problems on Playing cards probability:
What is the probability of getting a card of diamond?
(iv) a card of diamond. Number of favourable outcomes i.e. ‘a card of diamond’ is 13 out of 52 cards. Therefore, probability of getting ‘a card of diamond’ Number of favorable outcomes P(D) = Total number of possible outcome = 13/52 = 1/4 (v) a king or a queen. Total number of king is 4 out of 52 cards.