What is the action of hot HI on methyl and propyl ether?

When methyl -n-propyl ether is treated with hot HI methyl iodine and propyl iodide are formed.

What is obtained when ethyl methyl ether is treated with HI?

When ethyl methyl ether is treated with HI, it gives methyl iodide and ethyl alcohol.

What is the action of HI on methyl alcohol?

Action of cold HI on isopropyl methyl ether: When isopropyl methyl ether (mixed ether) is reacted with cold and conc. HI, methyl iodide (lower alkyl halide) and isopropyl alcohol (higher alcohol) is formed.

What is methyl propyl ether used for?

general anaesthetic
Methoxypropane, or methyl propyl ether, is an ether once used as a general anaesthetic. It is a clear colorless flammable liquid with a boiling point of 38.8 °C. Marketed under the trade names Metopryl and Neothyl, methoxypropane was used as an alternative to diethyl ether because of its greater potency.

What happens when ether reacts with HI?

When ethers are reacted with HI in cold temperature a cation is formed. This cation is reacted with HI which leads to the formation of methyl alcohol. A step-by-step process is followed by the SN1 reaction mechanism in which the carbocation is first formed from the removal of the leaving group.

What is the action of hot HI on methyl phenyl ether?

Phenol. Complete answer: When ethers heated in presence of HI it dissociates into alcohol and alkyl iodide.

What product are obtained when is treated with HI?

When an alkyl aryl ether is heated with HI, the halogen goes with alkyl group. Therefore, on heating anisole (methyl phenyl ether) with HI, phenol and methyl iodide are obtained.

What is the functional group of methyl propyl ether?

primary amine
This compound has the functional group primary amine with two carbons in its structure. Therefore, the correct answer for this question is option C. Additional information: Methoxypropane, or methyl propyl ether, was once used as a general anaesthetic.

What is the boiling point of dimethyl ether?

-11.2°F (-24°C)
Dimethyl ether/Boiling point

Why HI is better reagent than HBR in the cleavage of ether?

HI is a very strong acid as comparable to all halogen acids because it can easily donate H. On the other hand, I- is a very good leaving group. The mechanism of the cleavage of ether: The lone pairs of oxygen will attack at the hydrogen of HI and I- will leave.

Why does Phenylmethyl ether reacts with HI to give phenol and methyl iodide?

The reaction incolves the protonation of ether by acid followed by nucleophillic substitution by halide ion on the protonated ether. That is why in this reaction methyl iodide and phenol are formed and not methanol and phenyl iodide.