How do you find the XOR sum of an array?
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How do you find the XOR sum of an array?
We can find the XOR from index l to r using the formula: if l is not zero XOR = prefix[r] ^ prefix[l-1] else XOR = prefix[r]. After this, all we have to do is, to sum up, the XOR values of all the sub-arrays. Since a total number of sub-arrays is of the order (N2), the time complexity of this approach will be O(N2).
How do you find the smallest XOR of two numbers?
Smallest XOR
- calculate set bits in A (nA) and B(nB)
- if nA == nB then OUTPUT A.
- if nA > nB then. diff = nA – nB. remove diff set bits from right in A. and output ans.
- if nA < nB. diff = nB – nA. then change rightmost diff unset bits to set bits. and output it.
What is the fastest way to find XOR of two numbers?
To find each bit of XOR just calculate number of 1’s in the corresponding bits. If it is even or zero then that XOR’ed bit is 0. If it is odd then that XOR’ed bit is 1.
How do I find the of two numbers?
Answer: To find the percentage of a number between two numbers, divide one number with the other and then multiply the result by 100.
How do you find the XOR of two numbers in Python?
To get the logical xor of two or more variables in Python:
- Convert inputs to booleans.
- Use the bitwise xor operator ( ^ or operator. xor )
How do you Bitwise XOR in Python?
In Python, bitwise operators are used to performing bitwise calculations on integers….Bitwise operators.
| OPERATOR | DESCRIPTION | SYNTAX |
|---|---|---|
| & | Bitwise AND | x & y |
| | | Bitwise OR | x | y |
| ~ | Bitwise NOT | ~x |
| ^ | Bitwise XOR | x ^ y |
How do I find the numbers of XOR?
2 Answers
- If a[i] XOR b[i] = 0 and a[i] AND b[i] = 0 , then a[i] = b[i] = 0 .
- If a[i] XOR b[i] = 0 and a[i] AND b[i] = 1 , then a[i] = b[i] = 1 .
- If a[i] XOR b[i] = 1 and a[i] AND b[i] = 0 , then a[i] = 1 and b[i] = 0 or vice versa.
- It’s not possible to have a[i] XOR b[i] = 1 and a[i] AND b[i] = 1 .
What happens when you XOR two numbers?
This is based on the simple fact that XOR of a number with itself results Zero. and XOR of a number with 0 results the number itself. So, if we have an array = {5,8,12,5,12}.
How do you find the XOR of two numbers in Java?
{ int x = 5, y = 7; //declaring values. // bitwise XOR. // 0101 ^ 0111 = 0101 = 2….Java XOR Operator (Exclusive OR)
| x | y | x^y |
|---|---|---|
| 0 | 0 | 0 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 0 |