How much voltage does a transistor drop?

A general-purpose transistor will drop about . 1 to . 3 volts across the collector/emitter terminals (VCE(sat); see datasheet) when in saturation mode (fully on).

Is VBE always 0.7 V?

VBE is the voltage that falls between the base and emitter of a bipolar junction transistor. VBE is approximately 0.7V for a silicon transistor. For a germanium transistor (which is more rare), VBE is approximately 0.3V. Again, this formula, can be used for either silicon or germanium transistors.

How do you calculate VCE?

Calculate Vce using the formula Vce= Vcc – [Ie * (Rc + Re)]. Using the numbers from the previous examples, the equation works as follows: Vce = 12 – 0.00053 (3000 + 7000) = 12 – 5.3 = 6.7 volts.

How do you calculate VRC?

Vrc = Vb [Rc/Re]. This final equation gives us an easy definition for the voltage across the collector resistor that is independent of the beta (current gain) of the transistor, characteristic that varies widely among even the same batch of transistor, and that also depends on the temperature of the transistor.

What is the value of VBE in PNP transistor?

But in a pnp transistor the base is negative(n) and emitter is positive(p) so the vbe=-0.7V.

What is Vebo BJT?

The VEBO rating which you see in a transistor datasheet is the breakdown voltage rating for the emitter-base junction of the transistor. If so, the transistor can be destroyed and cause widespread damages to other parts of the circuit. Therefore, these ratings for a BJT are useful for these purposes.

How is voltage calculated in a transistor?

Determine the voltage drop between the collector and emitter junctions (Vce) of the transistor using the formula Vce = Vcc – IcRc, where “Vce” is the collector emitter voltage; “Vcc” is the supply voltage; and “IcRc” is the voltage drop across the base resistor (Rb).

How do you calculate IC and VCE?

Vce(sat) is usually something like 0.2V, and it’s usually safe to use 0V as a first approximation. If we assume Vce(sat) of 0V, we get an Ic = 10V/500 ohms = 0.02A. Now we calculate how much base current we need to put the transistor in saturation with an Ic of 0.02mA. Ib(min) = 0.02A / HFE = 0.0002A.

How do you find the transistor?

Ve = Vb – 0.7V. Vc = Vcc – Ie * Rc.