What should be the angular speed with which earth have to rotate about its own axis so that a person on the equator would weigh 1 5 times as much as present?
Table of Contents
- 1 What should be the angular speed with which earth have to rotate about its own axis so that a person on the equator would weigh 1 5 times as much as present?
- 2 What should be the angular velocity of earth about own axis so that a person’s weight at Equator will be of his weight at poles?
- 3 At what angular speed of the earth will the acceleration due to gravity at the equator of the earth becomes zero?
- 4 What should be angular velocity?
What should be the angular speed with which earth have to rotate about its own axis so that a person on the equator would weigh 1 5 times as much as present?
8×10−4 rad/sec.
What should be the angular speed with which the Earth have to rotate on its axis so that?
When calculating the angular velocity of the Earth as it completes a full rotation on its own axis (a solar day), this equation is represented as: ωavg = 2πrad/1day (86400 seconds), which works out to a moderate angular velocity of 7.2921159 × 10-5 radians/second.
What should the minimum angular speed of the earth be for objects to fly off its surface take G 10 ms 2 and RE 6400 km?
Therefore, angular speed of rotation of earth should be more than or equal to 1.237×10^-3 rad/s.
What should be the angular velocity of earth about own axis so that a person’s weight at Equator will be of his weight at poles?
8rad/s.
What should be earth’s angular speed?
ω = 1.99 x 10-7 radians /seconds. The angular speed of Earth is 1.99 x 10-7 radians /seconds.
What should be the angular speed of earth so that bodies lying on equator may appear weightlessness?
The angular speed of earth is “rad s”^(-1), so that the object on equator may appear weightless, is (radius of earth = 6400 km) ∴ω=√gR=√9.86400×103=1.23×10-3rad s-1.
At what angular speed of the earth will the acceleration due to gravity at the equator of the earth becomes zero?
10m/s2
The angular velocity of rotation of the earth in order to make the effective acceleration due to gravity equal to zero at equator should be g=10m/s2,R=6400km.
What should be the minimum angular speed of the earth?
This yields an angular escape velocity at the equator of 𝜔=11.2kms^-1/6378km=1.80·10^-3s^-1. For comparison, the angular velocity of the earth’s natural rotation is 7.27·10^-5s-1. Thus the earth’s rotation would have to speed up by a factor of 24.8 to let bodies at the equator escape the gravity of earth.
What should be angular velocity of earth?
What should be angular velocity?
By convention, positive angular velocity indicates counter-clockwise rotation, while negative is clockwise. . With orbital radius 42,000 km from the earth’s center, the satellite’s speed through space is thus v = 42,000 km × 0.26/h ≈ 11,000 km/h….
| Angular velocity | |
|---|---|
| Derivations from other quantities | ω = dθ / dt |
| Dimension |
What is the angular speed at the equator?
Angular Speed of the Earth
| Bibliographic Entry | Result (w/surrounding text) | Standardized Result |
|---|---|---|
| World Book Encyclopedia Vol 5. Illinois: Field Enterprises Educational Corporation:1961: 13. | “17.5 miles a minute at the equator is the speed of the earth. 0.0044 rad/min” | 7.367 × 10−5 rad/s |
What should be the angular speed of the earth so that body lying on equator may appear weightless?
Therefore the value of angular velocity of Earth for which object at equator becomes weightless is \[ 1.2\times {{10}^{-1}}\text{ rad }{{\text{s}}^{-1}}\] . So, the correct answer is “Option C”.