Why C2 is not exist?

The solution is as follows: Although C has 4 electrons that can be shared with another C, but we never see a compound like C. This is because, C has very small size and the orbitals of C are not able to overlap from all three direction to form 3 pi bonds and result into a very strained structure.

Does C2 exist according to molecular orbital theory?

Molecular orbital theory shows that it has two sets of paired electrons in a degenerate $\pi $- bonding set of orbitals. This gives a bond order of 2, which means that there should exist a double bond between the two carbons in a ${C_2}$ .

Why does C2 exist?

Molecular orbital theory shows that there are two sets of paired electrons in a degenerate pi bonding set of orbitals. Bond dissociation energies (BDE) of B2, C2, and N2 show increasing BDE, indicating single, double, and triple bonds, respectively.

Does C2 exist according to MOT?

Hint: Recall the molecular orbital theory (MOT) and write the electronic configuration of ${C_2}$ molecule according to MOT. You will find that the ${C_2}$ molecule has two sets of paired orbitals in the degenerate pi-bonding orbitals and bond order comes out to be 2.

Does C2 exist in vapour state?

C2 molecules have been found in vapour state. Their double bonds are made of two pi bonds because four electrons need to be accomodated in each bond. So this is against the rule that there must be a sigma bond before a pi bond is formed in the double bond.

Why does C2 have a bond order of 2?

If The Bond Order is Zero Then The Molecule Can’t Be Formed. So in C2; We can see both the Carbons are Doubly bonded,thus the Bond Order in C2 = 2.

Which of the following molecule does not exist Be2?

The electronic configuration of Beryllium is 1s2 2s2. From the electronic configuration it is clear that there is no singly filled atomic orbital present in beryllium. Without the half- filled orbital, the overlapping is not possible, therefore Be2 molecule does not exist.