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Which is more soluble NaCl or CsCl?

Which is more soluble NaCl or CsCl?

Therefore, CsCl is the least soluble of these group 1 chlorides, and NaCl is the most soluble.

Which is more soluble KCl or CsCl?

The covalent character decreases as size of cation increases LiCl > NaCl > KCl > RbCl > CsCl. Thus LiCl is more covalent than KCl and hence KCl is more soluble in water because of decreased covalent character.

Is KCl or NaCl more soluble?

NaCl is more soluble in water than KCl. The solubility of NaCl is 359 g/L at 200C and the solubility of KCl is 344 g/L at 200C.

Is RbCl least soluble in water?

RbCl is soluble. The solubility of common salts in water can be predicted using the solubility rules, which take into account the nature of the…

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Is RbCl more soluble than NaCl?

– Now, if we combine all these factors, then the solubility of the chlorides of the alkali metal decreases down the group. – Therefore, the order is NaCl > KCl > RbCl > CsCl.

Why is NaCl more soluble than KCl?

Sodium ion has smaller size than potassium ion.So sodium ion can more easily form a hydration sphere around it than potassium.So NaCl is more soluble than KCl.

Why is KCl least soluble?

Because the solubility of a compound mainly depends upon the hydration energy and lattice energy. If the hydration energy of the compound is greater than lattice energy, the solubility is more. Therefore, potassium chloride is insoluble in water.

Which is more basic NaCl or KCl?

KCl is more ionic because the ionic character increases as down the group while decreases along the period in the periodic table. Also, the bonding in KCl is more ionic than in NaCl. Electronegativity scales also support that NaCl is less ionic when compared to KCl.

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Why solubility of NaCl is more than KCl?

Is NaCl least soluble in water?

Table salt, or sodium chloride (NaCl), the most common ionic compound, is soluble in water (360 g/L). By contrast, when molecular compounds dissolve in water, it is the intermolecular forces between separate molecules that are disrupted.