How do you calculate work done by lifting?

As you are lifting the object you are doing work on the object. The work W done on an object by a constant force is defined as W = F·d. It is equal to the magnitude of the force, multiplied by the distance the object moves in the direction of the force.

How much work should be done in bringing a body of mass 10 kg to a height 5 Metre from the surface of earth?

∴ Work done, W =Fs =98×5J=490J .

What is work done by variable force?

Work done by a force can be divided into work from a constant force and work from a variable force. In the former kind, the magnitude and direction of the force remain unaltered. In such a case, work (W) is equal to the force applied (F) multiplied by displacement (Δx). Therefore, W = F x Δx.

How much force is required to lift a load of 20kg?

Answer: Force is the product of mass and acceleration which in this case is acceleration due to gravity. Thus the work done to lift the load is 196J.

What is the work done on lifting a body of mass 5kg vertically through 9m *?

Answer is correct. If you take g as 9.8 m/s^2 then answer will by 392 joule.

How do you calculate the force required to lift a 5kg?

Calculate the force required to lift the 5-kg mass 10 m. W = F × ∆d; where W is work, F is force, and ∆d is displacement. The unit for work is kg•m²/s², which is a Newton-meter, or N•m, and is called the Joule (J).

How strong is the force of gravity on 1 kg?

By the way, 1 kg exerts a weight force of around 9.81 N due to the gravity of the Earth and the distance between the point of measurement and the core of the Earth, so it might be different on other planets with different gravitational forces.

How do you calculate work done by an object in rotation?

Answer: Work is said to be done if a body undergoes displacement due to applied force. Work done = Force × Displacement Work done is zero by the moon, as there is no displacement since it is moving in a circular path. Question 54: State the amount of work done by an object when it moves in a circular path for one complete rotation.

What is the relation between Si and CGS units of force?

Write the relation between S. I. unit and C.G.S. unit of force. Answer: One Newton: If a body of mass 1 kg moves with an acceleration of 1 m/s 2 then force acting on the body is said to be one Newton. 1N = 10 5 Dyne. Relation between S. I. and CGS unit of force is 1 Newton = 1 kg × 1 ms -2.