Blog

What is the formula for when sodium reacts with oxygen?

What is the formula for when sodium reacts with oxygen?

Sodium is the metal reacts vigorously with oxygen and water. 4 Na + O2 → 2 Na2O.

What does sodium and oxygen yield?

Sodium reacts with oxygen to form sodium oxide and has the following balanced chemical equation: 4Na+O2→2Na2O 4 N a + O 2 → 2 N a 2 O .

How many molecules are in 64 grams of O2?

64 gram oxygen = 64/16 = 4 mole oxygen. “1 mole of any element contains 6.022 × 1023 atoms.” ∴ no. of atoms in 4 moles O2 = 4 × 6.022 × 1023 = 24.088 × 1023 atoms.

READ ALSO:   Is population variance a biased estimator?

How many grams of oxygen gas contains the same number of molecules as 16 gram of so2?

8 g
∴ 8 g of oxygen gas contain the same number of molecules as 16grams of sulphur dioxide gas.

How many grams of sodium sulfate will be formed if you start with 5.00 moles of sodium hydroxide and you have an excess of sulfuric acid?

Answer is 355 grams.

What happens when oxygen reacts with sodium answers com?

When burning sodium (Na) in oxygen (O2), you get sodium oxide (Na2O) and/or sodium peroxide (Na2O2). At high pressures, you can additionally get sodium superoxide (NaO2). 4 Na + O2 → 2 Na2O, and then partially 2 Na2O + O2 → 2 Na2O2.

What is the molecular mass of 62G of sodium oxide?

Sodium oxide is Na2O. It’s molecular mass is (23×2)+16 =62. In sodium oxide there are 2 sodium ions i.e in 62 g of sodium oxide there are 46g of sodium ions. 1 molecule of sodium oxide has = 2 sodium ions.

READ ALSO:   How should I watch the MCU for the first time?

What is the molecular mass of natrium oxide in N A2O?

By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol N a2O should result. The molecular mass of natrium oxide is 61.98 g ⋅ mol−1.

How many grams of calcium oxide are formed when oxygen reacts with calcium?

The answer is 5.61 grams. Thus, stoichiometrically, 1 mole of calcium (40.1 g) reacts with half a mole of oxygen (16 g) to give 1 mole of calcium oxide (56.1 g). From this it follows that 1.6 g oxygen can react only with 4.01 g of calcium metal to form 5.61 g of calcium oxide (answer).