What is the smallest number which when divided by 20 25 35 and 40?

Therefore, the smallest number which when divided by 20, 25, 35 and 40 and leaves a remainder of 14, 19, 29 and 34 respectively is 1394.

What is the smallest number which when divided by 20 25 35 40 leaves a remainder of 14 19 29 34 respectively?

1394
The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively, is 1394.

What is the largest number such that the same remainder is obtained if the numbers 31 103 and 247 are divided by it?

Answer: The largest number which divides 247 and 1031 leaving a reminder of 7 in each case is 16. ∴ The largest number which divides 247 and 1031 leaving a reminder of 7 in each case is 16.

Which is the largest number that divides 17/23 3559 to leave the same remainder in each case?

So, the largest number that divides 17, 23, 35, 59 is 6 which leaves the same remainder, 5, in each case. Answer.

What is the largest number that can divide 20 and 30 without a remainder?

10
What is HCF of 20 and 30? Answer: HCF of 20 and 30 is 10. Explanation: The HCF of two non-zero integers, x(20) and y(30), is the highest positive integer m(10) that divides both x(20) and y(30) without any remainder.

What are the largest 4-digit and smallest 3 digit?

Answer: Largest 4-digit number is 9999 and smallest 3-digit number is 100 and product is 10000.

What are the largest 4 digit and smallest 3 digit?

What largest number will divide 47 35 and 27 leaving same remainder in each case what will be the common remainder?

The common remainder is 3.

What is the greatest number that will divide 1305?

Hence, the answer is option (a) 4. Note: If we get HCF of 3360, 2240 and 5600 greater than 1305 then we should have to divide the HCF one by one with all the common factors of 3360, 2240 and 5600 and note the integer we get on dividing the HCF with each common factor.

What is the largest number which divides 62 132 and 237 and leaves the remainder in each case?

Thank you for asking this question: We will assume the largest number as x which will give as the same remainder which will be divided by 62,132 and 237. So 35 is the answer to this question.

What is the smallest number that can be divided by 35 and 40 without a remainder?

280
280; multiples of 40 = 40, 80, 120, 160 . . . . 280) and choose the smallest multiple that is exactly divisible by 35 and 40, i.e., 280.

What is the remainder of 114 divided by 19 and 21?

A number, when divided by 114, leaves remainder 21. If the same number is divided by 19, then the remainder will be 114 is divisible by 19 and 21 leaves a remainder of 2. SInce solving this problem algebraically is a very tedious process, let us put some values for a,b, and c. Then, we will try to match the options.

What is the least and greatest number exactly divisible by 5834?

The least number which when divided by 25, 40 and 60 leaves the remainder 7 in each case is The greatest number, which when subtracted from 5834, gives a number exactly divisible by each of 20, 28, 32 and 35, is If 21 is added to a number, it becomes 7 less than thrice of the number.

How do you find the least multiple of 13?

The least multiple of 13 which when divided by 4, 5, 6, 7 leaves remainder 3 in each case is put values of M and t accordingly and find least value of it. A number, when divided by 114, leaves remainder 21. If the same number is divided by 19, then the remainder will be 114 is divisible by 19 and 21 leaves a remainder of 2.