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How do you find the mass of a meter stick using torque?

How do you find the mass of a meter stick using torque?

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When you hang a mass from a meter stick what force is causing the torque in the meter stick?

So you have three forces providing torque to the meter stick: the weight of the unknown mass M pulling down on it, the weight of the 72-g mass pulling down on it, and its own weight pulling down on it.

How many forces act on the meter stick in the first part of your experiment?

three forces
In the first part, you will balance three forces on a meter stick and show that the net torque is zero when the meter stick is in equilibrium. In the second part you will balance the weight of the meter stick against a known weight to determine the mass of the meter stick.

How do you find the mass of a meter?

Divide the object’s weight by the acceleration of gravity to find the mass. You’ll need to convert the weight units to Newtons. For example, 1 kg = 9.807 N. If you’re measuring the mass of an object on Earth, divide the weight in Newtons by the acceleration of gravity on Earth (9.8 meters/second2) to get mass.

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How do you find the mass of a meter rule?

where m1 is the mass hanging from the rule, m2 is the mass of the metre rule and g is the acceleration of free fall. This can be rearranged to give m2 = m1 × (d1 / d2).

At what centimeter mark is that meter stick’s center of mass?

The average position of the weight of an object is its center of gravity, or CG. The CG of a uniform meter stick is at the 50-cm mark. In this experiment you will balance a meter stick with three known values (M1, M2, and X1). You will have to compute the unknown distance of X2.

What is the mass of a meter rule?

The mass of a metre rule will vary considerably depending upon the material of manufacture. Commonly they tend to have a mass of around 100 g, but given the variation it is a good idea to know the mass before the students carry out the activity.

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Why was the meter stick clamped at its center of gravity?

Because the center of gravity is off the pivot, the weight of the meter stick causes an extra torque. This torque is equal to the weight of the meter stick (Wbeam) times the 20cm distance that its center of gravity has from the pivot.