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How many moles of KOH are needed to neutralize moles of H2SO4?

How many moles of KOH are needed to neutralize moles of H2SO4?

For 98 grams of sulphuric acid 2 moles of potassium hydroxide is sufficient to neutralize.

How many moles of KOH are needed to neutralize 1.5 moles H2SO4?

1 Expert Answer The balanced reaction is as written. 2 KOH + H2SO4 —> 2 H2O + K2SO4. 1.5 moles H2SO4 ( 2 KOH/1 H2SO4) = 3 moles of KOH.

How many moles of NaOH did it take for the neutralization?

1 mole of NaOH produces 1 mole of OH- ions in solution. Therefore you will need 2 moles of NaOH to neutralize the 2 moles of H+ ions in solution.

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How many moles of H2SO4 are produced?

Based on our reaction equation, we know that 1 mole of sulfuric acid is produced for each mole for HCL used, so 0.0549 moles HCl * 1mole H2SO4/1moleHCL = 0.549 moles H2SO4.

How many moles of potassium hydroxide react with 1 mole of hydrochloric acid?

One mole of HCl reacts with one mole of KOH. 0.0025 moles of HCl react with 0.0025 moles of KOH.

How many moles of NaOH react with 1 mole of H2SO4?

2 moles
The ratio of NaOH to H2SO4 is 2:1. So you get 2 moles of NaOH for every 1 mole of H2SO4.

How many molecules of KOH does it take to neutralize H2SO4?

Because 1 molecule of H2SO4 gives 2 H+ ions per molecule while only one H+ ion is required to neutralize 1 molecule of KOH. So, 1 molecule of H2SO4 can neutralize 2 molecules of KOH. Hence, we would require 525 ml of 0.03 M H2SO4 to neutralize 525 ml of 0.06 M KOH.

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How many moles of H2SO4 are required to neutralize 2 moles NaOH?

From.the reaction we conclude that One mole of H2SO4 REACT WITH 2 MOLES OF NaOH It 0.1 moles of sulfuric acid will react. 980 gm of H2SO4 is required. It 0.1 moles of sulfuric acid will react. 980 gm of H2SO4 is required. From the above-mentioned reaction, we come to know that 1 mole of H 2 S O 4 is required to neutralize 2 moles of N a O H.

What is the balanced equation for the reaction between NaOH and H2SO4?

The balanced equation for the reaction is. H2SO4 + 2NaOH → Na2SO4 + 2H2O. So, 1 molecule of H2SO4 reacts with 2 molecules of NaOH and thence 1 mole of H2SO4 reacts with 2 moles of NaOH. As both solutions are of the same molarity, 1 ml of H2SO4 will neutralize 2 ml of NaOH.

How do you convert 8g of NaOH to moles?

This can be done with a periodic table. Then, divide your 8 grams by the mass of one mole of NaOH. The result is how much NaOH you have in moles. The final step is to divide this value by 2 (you only need half as much sulfuric acid) to get the quantity of H₂SO₄, in moles, required to neutralize the sodium hydroxide.