Questions

How many Faraday of electricity is required to reduce 1 mole of MnO4 minus ions to Mn 2 ions?

How many Faraday of electricity is required to reduce 1 mole of MnO4 minus ions to Mn 2 ions?

5 Faradays
How many faradays are required to reduce 1 mol of MnO_4^(-) to Mn^(2+)? 5 moles of e-=5 Faradays.

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How many Faraday are needed to reduce a mole of MnO4 to Mn 2?

five faradays
How many faradays are required to reduce one moleof MnO_(4)^(-) to Mn^(2+)? Number of faradays is equal to the change in oxidation state. Since oxidation state of Mn decreases by 5 units (from +7 to +2), five faradays is needed.

How much charge is required for the reduction of 1 mole of MnO4 to mn2 +?

where Q denotes the charge, n is the number of moles and F is the value of Faraday. Hence, we can say that the correct option is (D), that is the charge required for reducing 1 mole of $MnO_{4}^{-}$ to $M{{n}^{2+}}$ is $4.825\times {{10}^{5}}C$.

How much electricity in terms of Faraday is required for the conversion of MnO4 to Mn?

In the reaction 5 electrons are involved . Hence , 5 faraday will be needed for the reduction of 1 mole of MnO4- .

How many Faradays are required to reduce 1 mol of cr2o7 2 to CR 3 in acid medium?

3 Faraday charge is required.

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How many Faradays are required to reduce 1 mole of Bro 3 2b are?

1 mol contains 6.023*10^{23} atoms. 3*6.023*10^{23}*1.602*10^{-19}=3*96500\;Coulombs . We know 96500 \;Coulombs which is equal to 1 Faraday . The number of Faradays required is \frac{3*96500}{96500} =3\;Faradays .

How many coulombs of electricity are required for reduction of 1 mole of mno4?

93×105C.

How many coulombs are required for the reduction of 1 mol of mno4 to mn2+?

How many coulombs are required for the reduction of 1 mol of MNO 4 to Mn 2+?

What amount of electric charge is required for the reduction of 1 mole of cr2o72 to cr3+?

One mole Cr22O72- requires 6 moles of electrons for reduction.

How much electricity in terms of Faraday is produced by the oxidation of 1 mole of Zn?

So, for 1 mole of zinc ion, the number of electrons involved is 2 moles. We know that 1 F or 1 farad is the amount charge present in 1 mole of electrons. So, the total charge in the above reaction is 2F. Therefore, the quantity of electricity required to deposit one mole of zinc is 193000 coulombs.

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What amount of electric charge is required for the reduction of 1 mole of cr2o7?