Why Prims is better than Kruskal?

The advantage of Prim’s algorithm is its complexity, which is better than Kruskal’s algorithm. Therefore, Prim’s algorithm is helpful when dealing with dense graphs that have lots of edges. However, Prim’s algorithm doesn’t allow us much control over the chosen edges when multiple edges with the same weight occur.

What is the difference between Dijkstra’s Kruskal’s and Prim’s algorithms?

Both Prim’s and Kruskal’s algorithm finds the Minimum Spanning Tree and follow the Greedy approach of problem-solving, but there are few major differences between them….Difference between Prim’s and Kruskal’s algorithm for MST.

Prim’s Algorithm	Kruskal’s Algorithm
Prim’s algorithm runs faster in dense graphs.	Kruskal’s algorithm runs faster in sparse graphs.

Does Prims and Kruskal give same answer?

For there to be the possibility of multiple MSTs, at least two edges in the graph must be equal. Therefore, the MST is unique, and both Prim’s and Kruskal’s algorithm will return the same result.

What is the use of Prims and Kruskal algorithm?

Both Prims And Kruskal Algorithms are used to find the minimum spanning trees.

Which of the following is true about Kruskal’s and Prim’s algorithm?

Kruskal’s algorithm is best suited for the dense graphs than the prim’s algorithm. Explanation: Prim’s algorithm outperforms the Kruskal’s algorithm in case of the dense graphs. It is significantly faster if graph has more edges than the Kruskal’s algorithm.

Do Prim’s and Kruskal’s algorithms always find the same minimum spanning tree?

Prim’s and Kruskal’s algorithms will always return the same Minimum Spanning tree (MST). Prim’s algorithm for computing the MST only work if the weights are positive. An MST for a connected graph has exactly V-1 edges, V being the number of vertices in the graph.

Where we use Kruskal’s algorithm?

Kruskal’s Algorithm is used to find the minimum spanning tree for a connected weighted graph. The main target of the algorithm is to find the subset of edges by using which, we can traverse every vertex of the graph.